package test
import java.io.BufferedReader
import java.io.InputStreamReader
import java.net.HttpURLConnection
import java.net.URL
public class HttpTest {
private String u
private String encoding
public static void main(String[] args) throws Exception {
HttpTest client = new HttpTest("http://www.baidu.com/", "UTF-8")
client.run()
}
public HttpTest(String u, String encoding) {
this.u = u
this.encoding = encoding
}
public void run() throws Exception {
URL url = new URL(u)// 根据链接（字符串格式），生成一个URL对象
HttpURLConnection urlConnection = (HttpURLConnection) url
.openConnection()// 打开URL
BufferedReader reader = new BufferedReader(new InputStreamReader(
urlConnection.getInputStream(), encoding))// 得到输入流，即获得了网页的内容
String line// 读取输入流的数据，并显示
while ((line = reader.readLine()) != null) {
System.out.println(line)
}
}
}
根据具体问题类型，进行步骤拆解／原因原理分析／内容拓展等。
具体步骤如下：／导致这种情况的原因主要是……
1．编写useSourceViewer 类的基本框架，该类仅包括无返回值的main ()方法，该方法从参数中获取URL，通过输入缓冲和输出缓冲将该URL 原码输出。2．编写useSourceViewer 类，代码如下：
import java.net.*
import java.io.*
public class useSourceViewer
{
public static void main (String[] args)
{
if (args.length >0)
{
try
{
//读入URL
URL u = new URL(args[0])
InputStream in = u.openStream( )
// 为增加性能存储输入流
in = new BufferedInputStream(in)
// 将输入流连接到阅读器
Reader r = new InputStreamReader(in)
int c
while ((c = r.read( )) != -1)
{
System.out.print((char) c)
}
Object o = u.getContent( )
System.out.println("I got a " + o.getClass().getName( ))
}
catch (MalformedURLException e)
{
System.err.println(args[0] + " is not a parseable URL")
}
catch (IOException e)
{
System.err.println(e)
}
} // end if
} // end main
} // end SourceViewer}
