js判断添加多个标签

JavaScript021

js判断添加多个标签,第1张

js判断添加多个标签js怎么样获取多个标签内容-百度经验

1、创建一个test.html文件。

2、在文件内,使用ul、li标签创建一个测试的列表,同时创建一个button按钮,用于触发执行js函数。

3、在js标签内,

百度经验2020-01-12

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朋友,你好,开机亮了一下,就黑屏,这很可能是电源电路,高压板电路,灯管,这一条线出问题了,这是光的问题,所以你要着重看:电源电路的300V滤波大电容以及电源输出部份的滤波电容是否出现鼓包,放炮,等漏电现象,接着就是看灯管是否损坏了,可以用替换法,就知道灯管是不是坏了,然后就是看高压板电路的高压包是否出现内部线圈短路或者开路现象,热稳定不良现象,还有开关控制管是否被击穿 ,可调电阻损坏,这是最容易出现问题的一些元器件,所造成开机一亮,然后就暗屏的典型故障。

高压板电路图你这一款没有,你可以上网去搜一下,高压板电路不复杂,

希望我的回答对你有所帮助,祝你成功,快乐~~

const List = [{"end_date":"2022-02-10","end_seconds":1644488295.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-10 18:08:34","id":10319,"last_heart_beat_time":"2022-02-10 18:18:15","scanner_id":167,"start_date":"2022-02-10","start_seconds":1644487714.0,"start_total_seconds":581},{"end_date":"2022-02-11","end_seconds":1644550497.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 11:19:08","id":10338,"last_heart_beat_time":"2022-02-11 11:34:57","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644549548.0,"start_total_seconds":949},{"end_date":"2022-02-11","end_seconds":1644558220.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 11:48:41","id":10339,"last_heart_beat_time":"2022-02-11 13:43:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644551321.0,"start_total_seconds":6899},{"end_date":"2022-02-11","end_seconds":1644558820.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 13:53:40","id":10343,"last_heart_beat_time":"2022-02-11 13:53:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644558820.0,"start_total_seconds":0},{"end_date":"2022-02-11","end_seconds":1644563620.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 14:03:41","id":10344,"last_heart_beat_time":"2022-02-11 15:13:40","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644559421.0,"start_total_seconds":4199},{"end_date":"2022-02-11","end_seconds":1644586551.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-11 15:55:51","id":10350,"last_heart_beat_time":"2022-02-11 21:35:51","scanner_id":167,"start_date":"2022-02-11","start_seconds":1644566151.0,"start_total_seconds":20400},{"end_date":"2022-02-13","end_seconds":1644759468.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-13 14:47:48","id":10410,"last_heart_beat_time":"2022-02-13 21:37:48","scanner_id":167,"start_date":"2022-02-13","start_seconds":1644734868.0,"start_total_seconds":24600},{"end_date":"2022-02-14","end_seconds":1644846304.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-14 10:15:05","id":10430,"last_heart_beat_time":"2022-02-14 21:45:04","scanner_id":167,"start_date":"2022-02-14","start_seconds":1644804905.0,"start_total_seconds":41399},{"end_date":"2022-02-15","end_seconds":1644911999.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-15 15:30:00","id":10468,"last_heart_beat_time":"2022-02-15 15:59:59","scanner_id":167,"start_date":"2022-02-15","start_seconds":1644910200.0,"start_total_seconds":1799},{"end_date":"2022-02-15","end_seconds":1644932084.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-15 19:44:44","id":10472,"last_heart_beat_time":"2022-02-15 21:34:44","scanner_id":167,"start_date":"2022-02-15","start_seconds":1644925484.0,"start_total_seconds":6600},{"end_date":"2022-02-16","end_seconds":1645020217.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-16 15:13:37","id":10491,"last_heart_beat_time":"2022-02-16 22:03:37","scanner_id":167,"start_date":"2022-02-16","start_seconds":1644995617.0,"start_total_seconds":24600},{"end_date":"2022-02-17","end_seconds":1645089245.0,"end_total_seconds":0,"first_heart_beat_time":"2022-02-17 14:59:06","id":10521,"last_heart_beat_time":"2022-02-17 17:14:05","scanner_id":167,"start_date":"2022-02-17","start_seconds":1645081146.0,"start_total_seconds":8099}]

        const newArray = []

        List.forEach(item =>{

            // 第一次循环,repeat定义repet,基于find浅拷贝特性,操作repeat会影响到newArray

            // 循环开始,find的条件不成立,就会push一个新对象{data: item.start_date,times: [item]}进去

            // 检索条件要注意,find的核对条件需要准确

            // 第二次循环,find条件成立,则走else

            const repeat = newArray.find(res =>res.data === item.start_date)

            if (!repeat) {

                newArray.push({

                    data: item.start_date,

                    times: [item]

                })

            } else {

                // 避免循环紊乱,不用item.times.push(item),选用repeat.times.push(item)

                repeat.times.push(item)

            }

        })

打印数据后可以看到,已经将数据成功照相同时间的start_date重新管理

如果前端需要解决时间归类当天的用户多部操作但是后端没处理,就可以用forEach+find的方法处理