public static String[] getOneArray() {
String[] a = { "0", "1", "2" }
String[] b = { "0", "1", "2" }
String[] c = new String[a.length + b.length]
for (int j = 0 j < a.length ++j) {
c[j] = a[j]
}
for (int j = 0 j < b.length ++j) {
c[a.length + j] = b[j]
}
return c
}
public static Object[] getTwoArray() {
String[] a = { "0", "1", "2" }
String[] b = { "0", "1", "2" }
List aL = Arrays.asList(a)
List bL = Arrays.asList(b)
List resultList = new ArrayList()
resultList.addAll(aL)
resultList.addAll(bL)
Object[] result = resultList.toArray()
return result
}
public static String[] getThreeArray() {
String[] a = { "0", "1", "2", "3" }
String[] b = { "4", "5", "6", "7", "8" }
String[] c = new String[a.length + b.length]
System.arraycopy(a, 0, c, 0, a.length)
System.arraycopy(b, 0, c, a.length, b.length)
return c
}
Reference: http://www.cnblogs.com/changhongzhi/articles/2242323.html
int[] arr1 = {1,2,3,4,11}int[] arr2 = {6,7,8,9,10}
int newLength = arr1.length + arr2.length
int[] arr_target = new int[newLength]
//参数：源数组，源数组起始位置，目标数组，目标数组起始位置，复制长度
System.arraycopy(arr1, 0, arr_target, 0, arr1.length)
System.arraycopy(arr2, 0, arr_target, arr1.length, arr2.length)
//输出合并后数组
for (int i : arr_target) {
System.out.println(i)
}
//排序
Arrays.sort(arr_target)
//输出排序数组
for (int i : arr_target) {
System.out.println(i)
}
//逆序
int[] arr_reverse = new int[newLength]
int flag = 0
for (int i : arr_target) {
arr_reverse[newLength - flag - 1] = i
flag++
}
//输出逆序数组
for (int i : arr_reverse) {
System.out.println(i)
}
数组合并不一定非得遍历
具体的输出题主自己再修改吧
