js的数组合并有三种方法,任何一种都可以做到你需要的结果,如下:
concat 方法
var arr1=[{"msg":"你也好","from":"libai"},{"msg":"我是李白,你是谁","from":"libai"}]
var arr2=[{"msg":"你好","from":"admin"},{"msg":"LOL吗","from":"admin"},{"msg":"我是系统管理员,你是李白吗","from":"admin"}]
var arr=arr1.concat(arr2)console.log(c)//你要的结果,不改变arr1和arr2
循环遍历
var arr1=[{"msg":"你也好","from":"libai"},{"msg":"我是李白,你是谁","from":"libai"}]
var arr2=[{"msg":"你好","from":"admin"},{"msg":"LOL吗","from":"admin"},{"msg":"我是系统管理员,你是李白吗","from":"admin"}]
for(var i=0i<arr2.lengthi++){
arr1.push(arr2[i])
}
console.log(arr1)//你要的结果,但是这个是直接改变了arr1这个数组
apply方法
合并数组arr1和数组arr2,使用Array.prototype.push.apply(arr1,arr2) or arr1.push.apply(arr1,arr2)
var arr1=[{"msg":"你也好","from":"libai"},{"msg":"我是李白,你是谁","from":"libai"}]
var arr2=[{"msg":"你好","from":"admin"},{"msg":"LOL吗","from":"admin"},{"msg":"我是系统管理员,你是李白吗","from":"admin"}]
Array.prototype.push.apply(arr1,arr2) //或者 arr1.push.apply(arr1,arr2)
console.log(arr1) //改变了arr1
<script>
function extend(des, src, override){
if(src instanceof Array){
for(var i = 0, len = src.length i < len i++)
extend(des, src[i], override)
}
for( var i in src){
if(override || !(i in des)){
des[i] = src[i]
}
}
return des
}
var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}
var c = extend({}, [a,b])
</script>
这个算是比较好理解的了。