var num = parseFloat(str)
var strOutput = "",
strUnit = '仟佰拾亿仟佰拾万仟佰拾元角分'
num += "00"
var intPos = num.indexOf('.')
if (intPos >= 0){
num = num.substring(0, intPos) + num.substr(intPos + 1, 2)
}
strUnit = strUnit.substr(strUnit.length - num.length)
for (var i=0i <num.lengthi++){
strOutput += '零壹贰叁肆伍陆柒捌玖'.substr(num.substr(i,1),1) + strUnit.substr(i,1)
}
return strOutput.replace(/零角零分$/, '整').replace(/零[仟佰拾]/g, '零').replace(/零{2,}/g, '零').replace(/零([亿|万])/g, '$1').replace(/零+元/, '元').replace(/亿零{0,3}万/, '亿').replace(/^元/, "零元")
}
//代码如下所示：function convertCurrency(money) {
//汉字的数字
var cnNums = new Array('零', '壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖')
//基本单位
var cnIntRadice = new Array('', '拾', '佰', '仟')
//对应整数部分扩展单位
var cnIntUnits = new Array('', '万', '亿', '兆')
//对应小数部分单位
var cnDecUnits = new Array('角', '分', '毫', '厘')
//整数金额时后面跟的字符
var cnInteger = '整'
//整型完以后的单位
var cnIntLast = '元'
//最大处理的数字
var maxNum = 999999999999999.9999
//金额整数部分
var integerNum
//金额小数部分
var decimalNum
//输出的中文金额字符串
var chineseStr = ''
//分离金额后用的数组，预定义
var parts
if (money == '') { return '' }
money = parseFloat(money)
if (money >= maxNum) {
//超出最大处理数字
return ''
}
if (money == 0) {
chineseStr = cnNums[0] + cnIntLast + cnInteger
return chineseStr
}
//转换为字符串
money = money.toString()
if (money.indexOf('.') == -1) {
integerNum = money
decimalNum = ''
} else {
parts = money.split('.')
integerNum = parts[0]
decimalNum = parts[1].substr(0, 4)
}
//获取整型部分转换
if (parseInt(integerNum, 10) > 0) {
var zeroCount = 0
var IntLen = integerNum.length
for (var i = 0 i < IntLen i++) {
var n = integerNum.substr(i, 1)
var p = IntLen - i - 1
var q = p / 4
var m = p % 4
if (n == '0') {
zeroCount++
} else {
if (zeroCount > 0) {
chineseStr += cnNums[0]
}
//归零
zeroCount = 0
chineseStr += cnNums[parseInt(n)] + cnIntRadice[m]
}
if (m == 0 && zeroCount < 4) {
chineseStr += cnIntUnits[q]
}
}
chineseStr += cnIntLast
}
//小数部分
if (decimalNum != '') {
var decLen = decimalNum.length
for (var i = 0 i < decLen i++) {
var n = decimalNum.substr(i, 1)
if (n != '0') {
chineseStr += cnNums[Number(n)] + cnDecUnits[i]
}
}
}
if (chineseStr == '') {
chineseStr += cnNums[0] + cnIntLast + cnInteger
} else if (decimalNum == '') {
chineseStr += cnInteger
}
return chineseStr
}
