<tr>
<td width="109">数量</td>
<td width="41">单价</td>
<td width="91">金额</td>
</tr>
<tr>
<td name1="td11" onchange="sum()">10</td>
<td name1="td12"onchange="sum()">2</td>
<td name1="td13"onchange="sum()">20</td>
</tr>
<tr>
<td name1="td21"onchange="sum()">15</td>
<td name1="td22"onchange="sum()">3</td>
<td name1="td23"onchange="sum()">45</td>
</tr>
..
..
..
<tr>
<td name1="total1">合计数量：</td>
<td name1="total2" colspan="2">合计金额：</td>
</tr>
</table>
<script>
function sum()
{
var obj = document.getElementById("table1")
var length = obj.rows.length
var sum1 =0
var sum2 =0
for(int i=1i<length-1 i++)
{
sum1 =parseFloat(sum1) + parseFloat(document.getElementById ("td"+i+""+1).value)
sum2 =parseFloat(sum2) + parseFloat(document.getElementById ("td"+i+""+3).value)
}
document.getElementById ("total1").value = sum1
document.getElementById ("total2").value = sum2
}
</script>
每次点击触发newTd()，再调用total_menoy()的时候，执行each遍历，每次hj都会被置0，没记录之前的值。这里把var hj=0放到全局，也就是函数外边就可以了，然后还要在total-money中放一个hj的初始值2000。var pri = parseInt(document.getElementById('inpbox1').innerText)//单价var num = parseInt(document.getElementById('inpbox2').innerText)//数量
alert(pri*num)//弹出单价*数量的合计
