2、python计算两个时间之间的秒数
3、时间相加
计算当前时间向后10天的时间。参数可以是days, hours，minutes，seconds,microseconds,如果是负数就是向前多少时间其本上常用的类： datetime和timedelta两个。它们之间可以相互加减。每个类都有一些方法和属性可以查看具体的值，如 datetime可以查看：天数(day)，小时数(hour)，星期几(weekday())等timedelta可以查看：天数(days)，秒数 (seconds)等
from datetime import datetime
import math
def last_xmonth(x):now = datetime.now()
if x==0:
return now
else:
a = x%12 # 取余数 前a个月 限制0<a<12
b = math.ceil(x/12)+1 if x%12==0 else math.ceil(x/12) # 前b-1年
if x<now.month:
date1 = datetime.strftime(datetime(now.year-b+1,now.month-a,now.day),'%Y-%m-%d')
else :
date1 = datetime.strftime(datetime(now.year-b,now.month+12-a,now.day),'%Y-%m-%d')
return date1
# time模块实现, 也是自带的# 字符串不好计算~但是时间戳是固定的呀...
# 计算结果中, 假定今天24日, 输入24, 输出0天, 输入25, 输出-1天
import time
def f(tm):
stamp = time.mktime(time.strptime(tm, "%Y%m%d"))
diff = int((time.time() - stamp) // 86400)
if diff <= 180:
return {tm: str(diff)}
else:
d = {}
while diff > 180:
d[tm] = 180
stamp += 180 * 86400
diff = int((time.time() - stamp) // 86400)
# 注意这里time.gmtime()返回的是0时区日期, 需要处理时区问题
tm = time.strftime("%Y%m%d", time.gmtime(stamp - time.timezone))
else:
d[tm] = str(diff)
return d
if __name__ == '__main__':
tm = '20160325'
print(f(tm))
tm = '20171015'
print(f(tm))
# 结果输出, 注意: 字典是没有固定顺序的
'''
{'20160921': 180, '20170320': 180, '20170916': '38', '20160325': 180}
{'20171015': '9'}
'''
