请教MD5算法 用C语言实现

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请教MD5算法 用C语言实现,第1张

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#if defined(__APPLE__)

#  define COMMON_DIGEST_FOR_OPENSSL

#  include <CommonCrypto/CommonDigest.h>

#  define SHA1 CC_SHA1

#else

#  include <openssl/md5.h>

#endif

// 这是我自己写的函数,用于计算MD5

// 参数 str:要转换的字符串

// 参数 lengthL: 字符串的长度 可以用 strlen(str) 直接获取参数str的长度

// 返回值:MD5字符串

char *str2md5(const char * str, int length) {

    int n

    MD5_CTX c

    unsigned char digest[16]

    char *out = (char*)malloc(33)

    MD5_Init(&c)

    while (length > 0) {

        if (length > 512) {

            MD5_Update(&c, str, 512)

        } else {

            MD5_Update(&c, str, length)

        }

        length -= 512

        str += 512

    }

    MD5_Final(digest, &c)

    for (n = 0 n < 16 ++n) {

        snprintf(&(out[n*2]), 16*2, "%02x", (unsigned int)digest[n])

    }

    return out

}

    int main(int argc, char **argv) {

        char *output = str2md5("hello", strlen("hello"))

        

        printf("%s\n", output)

        // 上面会输出 hello的MD5字符串:

        // 5d41402abc4b2a76b9719d911017c592

        free(output)

        return 0

    }

#ifndef MD5_H

#define MD5_H

typedef struct

{

unsigned int count[2]

unsigned int state[4]

unsigned char buffer[64]

}MD5_CTX

#define F(x,y,z) ((x &y) | (~x &z))

#define G(x,y,z) ((x &z) | (y &~z))

#define H(x,y,z) (x^y^z)

#define I(x,y,z) (y ^ (x | ~z))

#define ROTATE_LEFT(x,n) ((x <<n) | (x >>(32-n)))

#define FF(a,b,c,d,x,s,ac) \

{ \

a += F(b,c,d) + x + ac\

a = ROTATE_LEFT(a,s)\

a += b\

}

#define GG(a,b,c,d,x,s,ac) \

{ \

a += G(b,c,d) + x + ac\

a = ROTATE_LEFT(a,s)\

a += b\

}

#define HH(a,b,c,d,x,s,ac) \

{ \

a += H(b,c,d) + x + ac\

a = ROTATE_LEFT(a,s)\

a += b\

}

#define II(a,b,c,d,x,s,ac) \

{ \

a += I(b,c,d) + x + ac\

a = ROTATE_LEFT(a,s)\

a += b\

}

void MD5Init(MD5_CTX *context)

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)

void MD5Final(MD5_CTX *context,unsigned char digest[16])

void MD5Transform(unsigned int state[4],unsigned char block[64])

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)

#endif

源文件md5.c

#include <memory.h>

#include "md5.h"

unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}

void MD5Init(MD5_CTX *context)

{

context->count[0] = 0

context->count[1] = 0

context->state[0] = 0x67452301

context->state[1] = 0xEFCDAB89

context->state[2] = 0x98BADCFE

context->state[3] = 0x10325476

}

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)

{

unsigned int i = 0,index = 0,partlen = 0

index = (context->count[0] >>3) &0x3F

partlen = 64 - index

context->count[0] += inputlen <<3

if(context->count[0] <(inputlen <<3))

context->count[1]++

context->count[1] += inputlen >>29

if(inputlen >= partlen)

{

memcpy(&context->buffer[index],input,partlen)

MD5Transform(context->state,context->buffer)

for(i = partleni+64 <= inputleni+=64)

MD5Transform(context->state,&input[i])

index = 0

}

else

{

i = 0

}

memcpy(&context->buffer[index],&input[i],inputlen-i)

}

void MD5Final(MD5_CTX *context,unsigned char digest[16])

{

unsigned int index = 0,padlen = 0

unsigned char bits[8]

index = (context->count[0] >>3) &0x3F

padlen = (index <56)?(56-index):(120-index)

MD5Encode(bits,context->count,8)

MD5Update(context,PADDING,padlen)

MD5Update(context,bits,8)

MD5Encode(digest,context->state,16)

}

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)

{

unsigned int i = 0,j = 0

while(j <len)

{

output[j] = input[i] &0xFF

output[j+1] = (input[i] >>8) &0xFF

output[j+2] = (input[i] >>16) &0xFF

output[j+3] = (input[i] >>24) &0xFF

i++

j+=4

}

}

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)

{

unsigned int i = 0,j = 0

while(j <len)

{

output[i] = (input[j]) |

(input[j+1] <<8) |

(input[j+2] <<16) |

(input[j+3] <<24)

i++

j+=4

}

}

void MD5Transform(unsigned int state[4],unsigned char block[64])

{

unsigned int a = state[0]

unsigned int b = state[1]

unsigned int c = state[2]

unsigned int d = state[3]

unsigned int x[64]

MD5Decode(x,block,64)

FF(a, b, c, d, x[ 0], 7, 0xd76aa478)/* 1 */

FF(d, a, b, c, x[ 1], 12, 0xe8c7b756)/* 2 */

FF(c, d, a, b, x[ 2], 17, 0x242070db)/* 3 */

FF(b, c, d, a, x[ 3], 22, 0xc1bdceee)/* 4 */

FF(a, b, c, d, x[ 4], 7, 0xf57c0faf)/* 5 */

FF(d, a, b, c, x[ 5], 12, 0x4787c62a)/* 6 */

FF(c, d, a, b, x[ 6], 17, 0xa8304613)/* 7 */

FF(b, c, d, a, x[ 7], 22, 0xfd469501)/* 8 */

FF(a, b, c, d, x[ 8], 7, 0x698098d8)/* 9 */

FF(d, a, b, c, x[ 9], 12, 0x8b44f7af)/* 10 */

FF(c, d, a, b, x[10], 17, 0xffff5bb1)/* 11 */

FF(b, c, d, a, x[11], 22, 0x895cd7be)/* 12 */

FF(a, b, c, d, x[12], 7, 0x6b901122)/* 13 */

FF(d, a, b, c, x[13], 12, 0xfd987193)/* 14 */

FF(c, d, a, b, x[14], 17, 0xa679438e)/* 15 */

FF(b, c, d, a, x[15], 22, 0x49b40821)/* 16 */