//YourFile.cpp (compiled into a .dll or .so file)
#include
//For std::nothrow
//Either include a header defining your class, or define it here.
extern "C" //Tells the compile to use C-linkage for the next scope.
{
//Note: The interface this linkage region needs to use C only.
void * CreateInstanceOfClass( void )
{
// Note: Inside the function body, I can use C++.
return new(std::nothrow) MyClass
}
//Thanks Chris.
void DeleteInstanceOfClass (void *ptr)
{
delete(std::nothrow) ptr
}
int CallMemberTest(void *ptr)
{
// Note: A downside here is the lack of type safety.
// You could always internally(in the C++ library) save a reference to all
// pointers created of type MyClass and verify it is an element in that
//structure.
//
// Per comments with Andre, we should avoid throwing exceptions.
try
{
MyClass * ref = reinterpret_cast
(ptr)
return ref->Test()
}
catch(...)
{
return -1//assuming -1 is an error condition.
}
}
} //End C linkage scope.
第二步：
gcc -shared -o test.so test.cpp
#creates test.so in your current working directory.
第三步：
>>>from ctypes import cdll
>>>stdc=cdll.LoadLibrary("libc.so.6") # or similar to load c library
>>>stdcpp=cdll.LoadLibrary("libstdc++.so.6") # or similar to load c++ library
>>>myLib=cdll.LoadLibrary("/path/to/test.so")
>>>spam = myLib.CreateInstanceOfClass()
>>>spam
[outputs the pointer address of the element]
>>>value=CallMemberTest(spam)
[does whatever Test does to the spam reference of the object]
今天遇到同样的问题，就来答一波吧
1，如果是在类中，那么就很简单了，类中的一个函数调用另一个函数，只要在那个被调用的函数前加self即可（图如下，详细可以参考笔者博客），
2，如果不是在类中，（这是笔者遇到的问题），有一个简单的方法，如下sin_f函数调用sin函数（注：a=sin()不能写到sin_f()函数下，会说a没声明就调用）：
3，如果是已经存在的包，那么调用包更简单了，（同样可以参考笔者上面给的那个博客第四部分）
4，最后，更多关于python问题可以参考笔者的python教程笔记
