代码框架如下:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char ch[20] = {0}
int choice = 0
while (1)
{
//...
//Add you coding here
//...
printf("1, continue 2, exit\n")
gets(ch)
choice = atoi(ch)
if (choice <= 0 || choice >=3)
{
printf("Your select error, input again!\n")
}
else if (choice == 1)
{
continue
}
else
{
exit(1)
//or
//break
}
}
return 0
}
当然情况多的话可以用case 语句实现~~~!
重复执行用循环就可以了..呵呵例如:
#include
int
main(void)
{
char
c
c
=
getchar()
while(c!='
')//输入空格退出
{
printf("%c",
c)//这里改成你需要的那个函数做相应的工作就可以了
c
=
getchar()
}
return
0
}
用goto 配上個 lable 就好了: #include<stdio.h>main(){ double p, w, s,d,fint t REDO: printf("请输入每公里每吨货物的\n运费P，货物重w，距离s\n") scanf("%lf,%lf,%lf",&p,&w,&s) if(s<0 || w<0 || p<0) { printf("二逼呀你，怎么会有运费或货种或路程是小于0的\n") exit(0) } else if(s<250) t=0else t=s/500+1 switch(t) { case 0: d=0break case 1: d=0.02break case 2: d=0.05break case 3: d=0.08break case 4: d=0.08break case 5: d=0.1break case 6: d=0.1break default: d=0.15 } f=p*w*s*(1-d) printf("总运费f=p*w*s*(1-d)=%lf\n",f)goto REDO}
