js计算两点之间的距离

JavaScript025

js计算两点之间的距离,第1张

getDistance: function (lat1, lng1, lat2, lng2) {

    lat1 = lat1 || 0

    lng1 = lng1 || 0

    lat2 = lat2 || 0

    lng2 = lng2 || 0

    var rad1 = lat1 * Math.PI / 180.0

    var rad2 = lat2 * Math.PI / 180.0

    var a = rad1 - rad2

    var b = lng1 * Math.PI / 180.0 - lng2 * Math.PI / 180.0

    var r = 6378137

    return r * 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(rad1) * Math.cos(rad2) * Math.pow(Math.sin(b / 2), 2)))

  }

import java.util.Scanner

public class Distance {

public static void main(String[] args) {

Line L = new Line(2,3,5)

Scanner sc = new Scanner(System.in)

System.out.println("输入点的x坐标：")

double x = sc.nextDouble()

System.out.println("输入点的y坐标：")

double y = sc.nextDouble()

System.out.println(distence(x,y,L))

}

public static double distence(double x,double y,Line L){

return Math.abs(L.A*x+L.B*y+L.C)/Math.sqrt(L.A*L.A+L.B*L.B)

}

}

class Line{//直线类,方程为：Ax+By+C=0

double A

double B

double C

public Line(double A,double B,double C){

this.A = A

this.B = B

this.C = C

}

}

let PI = 3.14159265358979323//圆周率

let R = 6371229//地球半径

function getDistance(lon1,lat1,lon2,lat2){

let x,y,distance

let lonres = lon1 >lon2?lon1-lon2:lon2-lon1

let latres = lat1 >lat2?lat1-lat2:lat2-lat1

x = (lonres) * PI * R * Math.cos(((lat1 + lat2) / 2) * PI / 180) / 180

y = (lat2 - lat1) * PI * R / 180

return distance = Math.hypot(x, y)

}