md5加密后javascript怎么解密

JavaScript024

md5加密后javascript怎么解密,第1张

无法解密,md5的特性就是只能加密,所以用md5加密的时候,一定要记住你填写的内容,否则只能用重置的办法才能解决忘记的问题了。

MD5加密步骤:

1、百度”站长工具“,点击打开。

2、然后点击导航里的”代码转换工具“,选择”MD5加密“。

3、然后输入欲加密的字符串,选择多少位,然后点击“加密”即可。

MD5不是加密算法,它是Hash算法,所以它不可逆,也没法还原成原文。

你可以用base64、异或或者aes des等加密算法去实现。

1、base64加密

在页面中引入base64.js文件,调用方法为:

?

123456789101112131415161718<!DOCTYPE HTML><html><head><meta charset="utf-8"><title>base64加密</title><script type="text/javascript" src="base64.js"></script><script type="text/javascript">  var b = new Base64()  var str = b.encode("admin:admin")  alert("base64 encode:" + str)//解密  str = b.decode(str)  alert("base64 decode:" + str)</script></head><body></body></html>

2、md5加密

在页面中引用md5.js文件,调用方法为

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1234567891011121314<!DOCTYPE HTML><html><head><meta charset="utf-8"><title>md5加密</title><script type="text/ecmascript" src="md5.js"></script><script type="text/javascript"> var hash = hex_md5("123dafd") alert(hash)</script></head><body></body></html>

3、sha1加密

据说这是最安全的加密

页面中引入sha1.js,调用方法为

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1234567891011121314<!DOCTYPE HTML><html><head><meta charset="utf-8"><title>sha1加密</title><script type="text/ecmascript" src="sha1.js"></script><script type="text/javascript"> var sha = hex_sha1('mima123465') alert(sha)</script></head><body></body></html>

一下为js们的源代码

base64.js:

?

123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106/**** Base64 encode / decode** @author haitao.tu* @date 2010-04-26* @email tuhaitao@foxmail.com**/function Base64() { // private property _keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=" // public method for encoding this.encode = function (input) {  var output = ""  var chr1, chr2, chr3, enc1, enc2, enc3, enc4  var i = 0  input = _utf8_encode(input)  while (i <input.length) {   chr1 = input.charCodeAt(i++)   chr2 = input.charCodeAt(i++)   chr3 = input.charCodeAt(i++)   enc1 = chr1 >>2   enc2 = ((chr1 &3) <<4) | (chr2 >>4)   enc3 = ((chr2 &15) <<2) | (chr3 >>6)   enc4 = chr3 &63   if (isNaN(chr2)) {    enc3 = enc4 = 64   } else if (isNaN(chr3)) {    enc4 = 64   }   output = output +   _keyStr.charAt(enc1) + _keyStr.charAt(enc2) +   _keyStr.charAt(enc3) + _keyStr.charAt(enc4)  }  return output } // public method for decoding this.decode = function (input) {  var output = ""  var chr1, chr2, chr3  var enc1, enc2, enc3, enc4  var i = 0  input = input.replace(/[^A-Za-z0-9\+\/\=]/g, "")  while (i <input.length) {   enc1 = _keyStr.indexOf(input.charAt(i++))   enc2 = _keyStr.indexOf(input.charAt(i++))   enc3 = _keyStr.indexOf(input.charAt(i++))   enc4 = _keyStr.indexOf(input.charAt(i++))   chr1 = (enc1 <<2) | (enc2 >>4)   chr2 = ((enc2 &15) <<4) | (enc3 >>2)   chr3 = ((enc3 &3) <<6) | enc4   output = output + String.fromCharCode(chr1)   if (enc3 != 64) {    output = output + String.fromCharCode(chr2)   }   if (enc4 != 64) {    output = output + String.fromCharCode(chr3)   }  }  output = _utf8_decode(output)  return output } // private method for UTF-8 encoding _utf8_encode = function (string) {  string = string.replace(/\r\n/g,"\n")  var utftext = ""  for (var n = 0n <string.lengthn++) {   var c = string.charCodeAt(n)   if (c <128) {    utftext += String.fromCharCode(c)   } else if((c >127) &&(c <2048)) {    utftext += String.fromCharCode((c >>6) | 192)    utftext += String.fromCharCode((c &63) | 128)   } else {    utftext += String.fromCharCode((c >>12) | 224)    utftext += String.fromCharCode(((c >>6) &63) | 128)    utftext += String.fromCharCode((c &63) | 128)   }  }  return utftext } // private method for UTF-8 decoding _utf8_decode = function (utftext) {  var string = ""  var i = 0  var c = c1 = c2 = 0  while ( i <utftext.length ) {   c = utftext.charCodeAt(i)   if (c <128) {    string += String.fromCharCode(c)    i++   } else if((c >191) &&(c <224)) {    c2 = utftext.charCodeAt(i+1)    string += String.fromCharCode(((c &31) <<6) | (c2 &63))    i += 2   } else {    c2 = utftext.charCodeAt(i+1)    c3 = utftext.charCodeAt(i+2)    string += String.fromCharCode(((c &15) <<12) | ((c2 &63) <<6) | (c3 &63))    i += 3   }  }  return string }}