url = require("url"),
path = require("path"),
fs = require("fs")
http.createServer(function (req, res) {
var pathname=__dirname+url.parse(req.url).pathname
if (path.extname(pathname)=="") {
pathname+="/"
}
if (pathname.charAt(pathname.length-1)=="/"){
pathname+="index.html"
}
path.exists(pathname,function(exists){
if(exists){
switch(path.extname(pathname)){
case ".html":
res.writeHead(200, {"Content-Type": "text/html"})
break
case ".js":
res.writeHead(200, {"Content-Type": "text/javascript"})
break
case ".css":
res.writeHead(200, {"Content-Type": "text/css"})
break
case ".gif":
res.writeHead(200, {"Content-Type": "image/gif"})
break
case ".jpg":
res.writeHead(200, {"Content-Type": "image/jpeg"})
break
case ".png":
res.writeHead(200, {"Content-Type": "image/png"})
break
default:
res.writeHead(200, {"Content-Type": "application/octet-stream"})
}
fs.readFile(pathname,function (err,data){
res.end(data)
})
} else {
res.writeHead(404, {"Content-Type": "text/html"})
res.end("<h1>404 Not Found</h1>")
}
})
}).listen(8080, "127.0.0.1")
console.log("Server running at http://127.0.0.1:8080/")
既然是返回的HTML,那么直接获取肯定是获取不到的,但是可以通过 加载顺序来解决这个问题。在返回的数据中加一个标识码,如果获取到这个标识码则代表已经正常返回 html , 这个时候再通过 获取dom 的方法去获取dom 就可以了。