python 怎么求标准正态分布某个值

Python024

python 怎么求标准正态分布某个值,第1张

示例:

1、from numpy import *

2、def rand_Matrix():

3、randArr=random.randn(2,3)

4、randMat=mat(randArr)

5、return randMat

一种结果如下:

1、matrix([[ 0.3150869 , -0.02041996, -0.15361071],

2、[-0.75507988,  0.80393683, -0.31790917]])

扩展资料

Python正态分布概率计算方法:

def st_norm(u):

'''标准正态分布'''

import math

x=abs(u)/math.sqrt(2)

T=(0.0705230784,0.0422820123,0.0092705272,

0.0001520143,0.0002765672,0.0000430638)

E=1-pow((1+sum([a*pow(x,(i+1))

for i,a in enumerate(T)])),-16)

p=0.5-0.5*E if u<0 else 0.5+0.5*E

return(p)

def norm(a,sigma,x):

'''一般正态分布'''

u=(x-a)/sigma

return(st_norm(u))

while 1:

'''输入一个数时默认为标准正态分布

输入三个数(空格隔开)时分别为期望、方差、x

输入 stop 停止'''

S=input('please input the parameters:\n')

if S=='stop':break

try:

L=[float(s) for s in S.split()]

except:

print('Input error!')

continue

if len(L)==1:

print('f(x)=%.5f'%st_norm(L[0]))

elif len(L)==3:

print('f(x)=%.5f'%norm(L[0],L[1],L[2]))

else:

print('Input error!')

Python正态分布概率计算方法,喜欢算法的伙伴们可以参考学习下。需要用到math模块。先了解一下这个模块方法,再来写代码会更好上手。

def st_norm(u):

'''标准正态分布'''

import math

x=abs(u)/math.sqrt(2)

T=(0.0705230784,0.0422820123,0.0092705272,

0.0001520143,0.0002765672,0.0000430638)

E=1-pow((1+sum([a*pow(x,(i+1))

for i,a in enumerate(T)])),-16)

p=0.5-0.5*E if u<0 else 0.5+0.5*E

return(p)

def norm(a,sigma,x):

'''一般正态分布'''

u=(x-a)/sigma

return(st_norm(u))

while 1:

'''输入一个数时默认为标准正态分布

输入三个数(空格隔开)时分别为期望、方差、x

输入 stop 停止'''

S=input('please input the parameters:\n')

if S=='stop':break

try:

L=[float(s) for s in S.split()]

except:

print('Input error!')

continue

if len(L)==1:

print('f(x)=%.5f'%st_norm(L[0]))

elif len(L)==3:

print('f(x)=%.5f'%norm(L[0],L[1],L[2]))

else:

print('Input error!')