可以用这样的方法来实现:
#include<stdio.h>
#include<math.h>
int main()
{ char *a[]= {"22","33","44","The end"}
int i
for(i=0i<sizeof(a)/sizeof(a[0])i++)
printf("%s\n",a[i])
return 0
}
可以用这样的方法来实现:
#include<stdio.h>
#include<math.h>
int main()
{ char *a[]= {"22","33","44","The end"}
int i
for(i=0i<sizeof(a)/sizeof(a[0])i++)
printf("%s\n",a[i])
return 0
}