#include <stdio.h>
#include <math.h>
int vanum(int m){
Int i,n=0
for(i=2i<mi++){
if(m%i==0)
n++
}
if(n==0)
return m
else
return 0
}
int main(void)
{
int i=0,k,m,n,a[N]
printf("Input M &N.\n")
scanf("%d %d",&m,&n)
while(i<n){
k=vanum(++m)
if(k!=0){
a[i]=k
i++
}
}
for(i=0i<ni++){
printf("%4d,",a[i])
}
return 0
}
main函数写的有问题，应该类似如下：FILE *a，*b；
char wjm[200]
puts("请输入源文件名："）； gets（wjm ）； a= fopen( wjm, "r+")
puts("请输入目标文件名："）； gets（wjm ）； b= fopen( wjm, "w+")
if( a &&b ) jyt ( a, b )
fcloseall()
#include "stdafx.h"#include <stdio.h> //身份证号码升级
int main()
{
int i,wi=0
char sh[19],a[4]
int w[17]={7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2}
char y[12]={"10x98765432"}
printf("请输入15位身份证号码:")
scanf("%s",sh)
printf("\n")
for(i=15i>=6i--)
sh[i+2]=sh[i]
sh[6]='1'sh[7]='9'
printf("\n")
for(i=0i<17i++)
wi+=(sh[i]-'0')*w[i]
sh[17]=y[wi%11]
sh[18]='\0'
printf("18位身份证号码是:%s\n",sh)
}
汇编：
int main()
{
000B6C26 inc ebp
000B6C27 cld
int i, wi = 0
000B6C28 mov dword ptr [wi],0
char sh[19]
int w[17] = { 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 }
000B6C2F mov dword ptr [w],7
000B6C36 mov dword ptr [ebp-7Ch],9
000B6C3D mov dword ptr [ebp-78h],0Ah
000B6C44 mov dword ptr [ebp-74h],5
000B6C4B mov dword ptr [ebp-70h],8
000B6C52 mov dword ptr [ebp-6Ch],4
000B6C59 mov dword ptr [ebp-68h],2
000B6C60 mov dword ptr [ebp-64h],1
000B6C67 mov dword ptr [ebp-60h],6
000B6C6E ?? ??
000B6C6F ?? ??
000B6C70 ?? ??
000B6C71 ?? ??
000B6C72 add byte ptr [eax],al
000B6C74 add bh,al
000B6C76 inc ebp
000B6C77 testal,7
000B6C79 add byte ptr [eax],al
000B6C7B add bh,al
000B6C7D inc ebp
000B6C7E lodsbyte ptr [esi]
char sh[19]
int w[17] = { 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 }
000B6C7F or dword ptr [eax],eax
000B6C81 add byte ptr [eax],al
000B6C83 mov dword ptr [ebp-50h],0Ah
000B6C8A mov dword ptr [ebp-4Ch],5
000B6C91 mov dword ptr [ebp-48h],8
000B6C98 mov dword ptr [ebp-44h],4
000B6C9F mov dword ptr [ebp-40h],2
char y[12] = { "10x98765432" }
000B6CA6 mov eax,dword ptr ds:[000BED84h]
000B6CAB mov dword ptr [y],eax
000B6CB1 mov ecx,dword ptr ds:[0BED88h]
000B6CB7 mov dword ptr [ebp-90h],ecx
000B6CBD mov edx,dword ptr ds:[0BED8Ch]
char y[12] = { "10x98765432" }
000B6CC3 mov dword ptr [ebp-8Ch],edx
cout<<"请输入15位身份证号码:"
000B6CC9 push0BED94h
000B6CCE mov eax,dword ptr ds:[000C20C0h]
000B6CD3 pusheax
000B6CD4 callstd::operator<<<std::char_traits<char>>(0B1302h)
000B6CD9 add esp,8
cin >>sh
000B6CDC lea eax,[sh]
000B6CDF pusheax
000B6CE0 mov ecx,dword ptr ds:[0C20BCh]
000B6CE6 pushecx
000B6CE7 callstd::operator>><char,std::char_traits<char>>(0B10E1h)
000B6CEC add esp,8
for (i = 15i >= 6i--)
000B6CEF mov dword ptr [i],0Fh
000B6CF6 jmp main+101h (0B6D01h)
000B6CF8 mov eax,dword ptr [i]
000B6CFB sub eax,1
000B6CFE mov dword ptr [i],eax
000B6D01 cmp dword ptr [i],6
000B6D05 jl main+117h (0B6D17h)
sh[i + 2] = sh[i]
000B6D07 mov eax,dword ptr [i]
000B6D0A mov ecx,dword ptr [i]
000B6D0D mov dl,byte ptr sh[ecx]
000B6D11 mov byte ptr [ebp+eax-32h],dl
000B6D15 jmp main+0F8h (0B6CF8h)
sh[6] = '1'sh[7] = '9'
000B6D17 mov eax,1
000B6D1C imulecx,eax,6
000B6D1F mov byte ptr sh[ecx],31h
000B6D24 mov eax,1
000B6D29 imulecx,eax,7
000B6D2C mov byte ptr sh[ecx],39h
printf("\n")
000B6D31 mov esi,esp
000B6D33 push0BEDB0h
000B6D38 calldword ptr ds:[0C2220h]
000B6D3E add esp,4
000B6D41 cmp esi,esp
000B6D43 call__RTC_CheckEsp (0B1398h)
for (i = 0i<17i++)
000B6D48 mov dword ptr [i],0
000B6D4F jmp main+15Ah (0B6D5Ah)
000B6D51 mov eax,dword ptr [i]
000B6D54 add eax,1
000B6D57 mov dword ptr [i],eax
000B6D5A cmp dword ptr [i],11h
000B6D5E jge main+17Bh (0B6D7Bh)
wi += (sh[i] - '0')*w[i]
000B6D60 mov eax,dword ptr [i]
000B6D63 movsx ecx,byte ptr sh[eax]
000B6D68 sub ecx,30h
000B6D6B mov edx,dword ptr [i]
000B6D6E imulecx,dword ptr w[edx*4]
000B6D73 add ecx,dword ptr [wi]
000B6D76 mov dword ptr [wi],ecx
000B6D79 jmp main+151h (0B6D51h)
sh[17] = y[wi % 11]
000B6D7B mov eax,dword ptr [wi]
000B6D7E cdq
000B6D7F mov ecx,0Bh
000B6D84 idiveax,ecx
000B6D86 mov eax,1
000B6D8B imulecx,eax,11h
000B6D8E mov dl,byte ptr y[edx]
000B6D95 mov byte ptr sh[ecx],dl
sh[18] = '\0'
000B6D99 mov eax,1
sh[18] = '\0'
000B6D9E imulecx,eax,12h
000B6DA1 mov dword ptr [ebp-160h],ecx
000B6DA7 cmp dword ptr [ebp-160h],13h
000B6DAE jae main+1B2h (0B6DB2h)
000B6DB0 jmp main+1B7h (0B6DB7h)
000B6DB2 call___report_rangecheckfailure (0B1415h)
000B6DB7 mov edx,dword ptr [ebp-160h]
000B6DBD mov byte ptr sh[edx],0
cout <<"18位身份证号码是:" <<sh <<"\n"
000B6DC2 push0BEDB0h
000B6DC7 lea eax,[sh]
000B6DCA pusheax
000B6DCB push0BEDB4h
000B6DD0 mov ecx,dword ptr ds:[0C20C0h]
000B6DD6 pushecx
000B6DD7 callstd::operator<<<std::char_traits<char>>(0B1302h)
000B6DDC add esp,8
000B6DDF pusheax
000B6DE0 callstd::operator<<<std::char_traits<char>>(0B1302h)
000B6DE5 add esp,8
000B6DE8 pusheax
000B6DE9 callstd::operator<<<std::char_traits<char>>(0B1302h)
000B6DEE add esp,8
}
000B6DF1 jmp main+1F5h (0B6DF5h)
000B6DF3 jmp main+1F7h (0B6DF7h)
000B6DF5 xor eax,eax
000B6DF7 pushedx
000B6DF8 mov ecx,ebp
000B6DFA pusheax
000B6DFB lea edx,ds:[0B6E28h]
000B6E01 call@_RTC_CheckStackVars@8 (0B1159h)
000B6E06 pop eax
000B6E07 pop edx
000B6E08 pop edi
000B6E09 pop esi
000B6E0A pop ebx
000B6E0B mov ecx,dword ptr [ebp-4]
000B6E0E xor ecx,ebp
000B6E10 call@__security_check_cookie@4 (0B1050h)
000B6E15 add esp,164h
000B6E1B cmp ebp,esp
000B6E1D call__RTC_CheckEsp (0B1398h)
000B6E22 mov esp,ebp
000B6E24 pop ebp
000B6E25 ret
000B6E26 mov edi,edi
000B6E28 add eax,dword ptr [eax]
000B6E2A add byte ptr [eax],al
000B6E2C xor byte ptr [esi+0Bh],ch
000B6E2F add ah,cl
000B6E31 ?? ??
000B6E32 ?? ??
000B6E33 calldword ptr [ebx]
000B6E35 add byte ptr [eax],al
000B6E37 add byte ptr [eax+6Eh],bl
000B6E3A or eax,dword ptr [eax]
000B6E3C cmp bh,0FFh
000B6E3F inc dword ptr [eax+eax]
000B6E43 add byte ptr [esi+6Eh],dl
000B6E46 or eax,dword ptr [eax]
000B6E48 ins byte ptr es:[edi],dx
000B6E49 ?? ??
000B6E4A ?? ??
000B6E4B dec dword ptr [eax+eax]
000B6E4E add byte ptr [eax],al
000B6E50 pushesp
000B6E51 outsdx,byte ptr [esi]
000B6E52 or eax,dword ptr [eax]
000B6E54 jns main+256h (0B6E56h)
000B6E56 ja main+258h (0B6E58h)
000B6E58 jae _main+2C2h (0B6EC2h)
000B6E5A add ah,cl
