#include <string.h>
bool isLeapYear(int)
int getWeekDay(int, int, int)
int main(int argc, char const *argv[])
{
int year
int month
printf("输入日期(yyyy-mm):")
scanf("%d-%d-%d", &year, &month)//输入年和月
printf(" %d年%d月\n", year, month)//输出日历日历标题
printf("日 一 二 三 四 五 六\n")//输出星期
//本函数获取某个日期是星期几，这里获取每月的1号是星期几，返回是是[0-7]对应(星期天-星期六)
int week = getWeekDay(year, month, 1)
int i
for (i = 0i <weeki++)//每月第一周前几天用空格填充
printf(" ")
int endDayOfMonth//每个月的最后一天
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12)
endDayOfMonth = 31
else if (month == 2)
{
if (isLeapYear(year))
endDayOfMonth = 29
else
endDayOfMonth = 28
}
else
endDayOfMonth = 30
int dayOfMonth = 1
//从一号循环到本月末
while (dayOfMonth <= endDayOfMonth)
{
printf("%2d ", dayOfMonth)
dayOfMonth++
//每输出完星期六的日期后就换行(对应周数起点是从week开始的，所以要在天数上加上week)
if ((dayOfMonth + week- 1) % 7 == 0)
printf("\n")
}
printf("\n")
return 0
}
//判断闰年
bool isLeapYear(int y)
{
if (y % 4 == 0 &&y % 100 != 0 || y % 400 == 0)
return true
return false
}
//获取某天是星期几返回值(0-7)
int getWeekDay(int y, int m, int d)
{
//计算星期几的固定公式,Y是年D是这个日期在本年的天数
//W = [Y-1] + [(Y-1)/4] - [(Y-1)/100] + [(Y-1)/400] + D
int days = d
int i
for (i = 1i <mi++)
{
if (i == 1 || i == 3 || i == 5 || i == 7 || i == 8 || i == 10 || i == 12)
days += 31
else if (i == 2)
{
if (isLeapYear(y))
days += 29
else
days += 28
}
else
days += 30
}
int temp = y - 1 + (int)((y - 1) / 4) - (int)((y - 1) / 100) + (int)((y - 1) / 400) + days
return temp % 7
}
