def get_element(data):
dic = {}
i = 0
while i <len(data):
if data[i] in dic:
"""
循环查找列表元素,如果一个元素出现一次,value就等于1,多次出现,value就增加
"""
dic[data[i]] += 1
else:
dic[data[i]] = 1
i += 1
for j, k in dic.items():
if k >1:
print('data数组中重复的元素有%d,它的个数是%d个'%(j,k))
print(dic)
my_list =[1,2,3,4,2,4,2,3,4,5,6,23,23,32]
get_element(my_list)
以下代码会打印输出,列表nums中存在重复的数字:
nums = [1,1,2,2,3,3,4,5,6,6,7,8]
repeat = [ i for i in set(nums) if nums.count(i) >1 ]
print(repeat)
输出:
[1, 2, 3, 6]