list= [1,2,3,4,5,1,2,2]
list.index(2) >>>>>>>>1
如果要获取相同值的最后一个索引:
len(list) - list[::-1].index(2) - 1
反向取得list后,用list的长度减去反转后出现的第一个索引再减1
使用Here键。Here是获取Python3中OrderedDict的最后一个键的方法.我需要在Python3中获取OrderedDict的最后一个值,而无需转换为列表.
Python 3.4.0 (default, Apr 11 2014, 13:05:11)
>>>from collections import OrderedDict
>>>dd = OrderedDict(a=1, b=2)
>>>next(reversed(dd))
'b'
>>>next(reversed(dd.keys()))
Traceback (most recent call last):
File "", line 1, in
TypeError: argument to reversed() must be a sequence
>>>next(reversed(dd.items()))
Traceback (most recent call last):
File "", line 1, in
TypeError: argument to reversed() must be a sequence
>>>next(reversed(dd.values()))
Traceback (most recent call last):
File "", line 1, in
TypeError: agument to reversed() must be a sequence