def print_row(n):
print list1[n]
print list2[n]
print list3[n]
def operate():
for i in range(5):
if list1[i] == 0:
print_row(i)
elif list2[i] == 0:
print_row(i)
elif list3[i] == 0:
print_row(i)
else:
continue
if __name__ == '__main__':
list1 = [0, 1, 2, 3, 4]
list2 = [1, 2, 3, 4, 0]
list3 = [2, 3, 4, 0, 1]
operate()
a = [[0,1,2],['a','b','c'],
[7,8,9]]
print(a[2][1])
因为都是从0开始数,取第三行第二个元素就是2,1