a.sort(key=lambda x: str(len(x)) + x)
print(a)
#['a', 'b', 'c', 'aa', 'ab', 'aaa']
不过,我还是用正则表达式的方法帮你排了一下序,如果你要数字从小到大排序,只要把alist.sort(key=sort_key,reverse=True)改成alist.sort(key=sort_key,reverse=False)就行了.
完整的Python程序如下
import redef sort_key(s):
if s:
try:
c = re.findall('\d+$', s)[0]
except:
c = -1
return int(c)
def strsort(alist):
alist.sort(key=sort_key,reverse=True)
return alist
A=['abc 15','abd 13','abe 9','abf 6','abg 2']
print(strsort(A))