int a,b,c,d,e,h,flag/*5家井长分别为a,b,c,d,e,井深为h*/
flag=0
for(h=7h<1000h++)
{
for(e=1e<h/6e++)
{
a=h-6*e
b=h-2*a
c=h-3*b
d=h-4*c
if(b==1||c<1||d<1)
{
continue
}
if(h==e+d*5)
{
flag=1
goto END
}
}
}
END:if(1==flag)
{
printf("五家的绳长分别为：\n")
printf("a=%d\n",a)
printf("b=%d\n",b)
printf("c=%d\n",c)
printf("d=%d\n",d)
printf("e=%d\n",e)
printf("井深:\n")
printf("h=%d\n",h)
}
#include<stdio.h>void main()
{ int x,y,z,a,b/*甲x,乙y,丙z,丁a,戊b*/
/*依题意: 2x+y==3y+z==4z+a==5a+b==6b+x
故推知: x=y+z/2 (z是偶数)
y=z+a/3 (a是3的倍数)
z=a+b/4 (b是4的倍数)
a=b+x/5 (x是5的倍数)
*/
for(b=4b+=4)
for(x=5x+=5)
{ a=b+x/5
z=a+b/4
if(z%2)continue
if(a%3)continue
y=z+a/3
if(y+z/2<x)break
if(y+z/2==x){
printf("%d,%d,%d,%d,%d\n",x,y,z,a,b)return}
}
}
