n在哪里?怎么个有关法?阴影部分的面积不就是(x-1)^2+1在[1,2]上积分吗?
#include "stdio.h"int main(int argc,char *argv[]){
double s,x,t
for(t=1.0E-6,s=x=0x<=2s+=((x-1)*(x-1)+1)*t,x+=t)
printf("s≈%g\n",s)
return 0
}
#include<stdio.h>#define PI 3.14159
int main()
{
int a,n
float s
scanf("%d%d",&a,&n)
s=(a*a-PI*a*a/4)*n*n
printf("%.2f",s)
}
不懂可问