string = input() #string == '1 2 3 4 5'
l = string.split(' ')
for i in range(len(l)):
....l[i] = int(l[i])
l.reverse()
for i in range(len(l1)):
....print(l[i], end='')
....if l[i] != l[-1]: print(',', end='')
第二个
string = input() #string == '[1,2,3,4,5]'
string = string[1:-1]
l = string.split(',')
for i in range(len(l)):
....l[i] = int(l[i])
l.reverse()
print(repr(l).replace(', ', ','))
第三个其实跟第一个差不多,split(' ')换成split(','),删掉reverse()这一步,然后直接输出列表就行。
num = [1,2,3,4]for i in range(0, num.__len__())[::-1]:
print num[i]
输出:
4
3
2
1
def r(a):count=0
for i in range(len(a)):
for j in range(i):
if a[i]<a[j]:
count++
return count
a=[9,5,2,4]
print(r(a))