public class test {
public static void main(String[] args) {
int x,y //x:鸡 y:兔
for(x=0x<=35x++) { //遍历鸡的只数
y=35-x //兔的只数等于35 - 鸡
if(2*x+4*y==94) //如果鸡和兔的脚总数是94
System.out.println("鸡"+x+"只,兔"+y+"只")
}
}
}
用“java”实现鸡兔同笼问题如下:
System.out.println("---------鸡兔同笼问题------")
int head, foot
int ji[] = { 0 }, tu[] = { 0 }
System.out.print("输入头数:")
Scanner scanner = new Scanner(System.in)
head = scanner.nextInt()
System.out.print("输入脚数:")
foot = scanner.nextInt()
JTTL(head,foot,tu,ji)
System.out.println("鸡有"+ji[0]+"个"+","+"兔有"+tu[0]+"个")
}
private static void JTTL(int head, int foot, int[] tu, int[] ji) {// TODO Auto-generated method stubtu[0]=foot/2-headji[0]=2*head-foot/2}}