=>[1, 2, 5, 3, 9, 0, 9]
irb(main):002:0>a-[2]
=>[1, 5, 3, 9, 0, 9]
irb(main):004:0>a
=>[1, 2, 5, 3, 9, 0, 9]
irb(main):005:0>a-[4]
=>[1, 2, 5, 3, 9, 0, 9]
public static void main(String[] args){
int [] num =new int[]{1,2,3,4,5,6,7,8,9,10}
Scanner input = new Scanner(System.in)
int temp=0
System.out.println("请输入你要删除的元素:")
int de=input.nextInt()
for(int i =0i<num.lengthi++)
{
if(num[i]==de)
{
for(int j = ij<num.length-1j++)
{
num[j]=num[j+1]
}
temp=1
break
}
}
if(temp==1)
{
System.out.println("删除此对象后数组值为：")
for(int i = 0i<num.length-1i++)
{
System.out.print(num[i]+"\t")
}
}
else
{
System.out.println("未找到你要删除的对象")
}
}
