result := ""
for _, i := range arr {
result += strconv.FormatUint(i, 10) + char
}
return strings.Trim(result,char)
}
提取前两位,然后把这个子串装入数组即可。如果字符串有一定规律,如 s =“23-3-4-2”
可以按照String[] str = s.split("-")这样可以按照“-”拆分字符串成字符数组。
举例:
//字符串数组String[] arrs=new String[]{"1","2","3","4","5"}
StringBuilder sb=new StringBuilder()
for(String s:arrs){
sb.append(s)
}
String result=sb.toString()
System.out.println(result)
//整形数组
int[] arrs2=new int[]{1,2,3,4,5}
StringBuilder sb2=new StringBuilder()
for(int num:arrs2){
sb2.append(num)
}
String result2=sb2.toString()
System.out.println(result2)