![js中有["1","2","3","4"]这样一个string，怎么把它变成array](/aiimages/js%E4%B8%AD%E6%9C%89%5B%26quot%3B1%26quot%3B%2C%26quot%3B2%26quot%3B%2C%26quot%3B3%26quot%3B%2C%26quot%3B4%26quot%3B%5D%E8%BF%99%E6%A0%B7%E4%B8%80%E4%B8%AAstring%EF%BC%8C%E6%80%8E%E4%B9%88%E6%8A%8A%E5%AE%83%E5%8F%98%E6%88%90array.png)
if(objObject.IPEnabled != null &&objObject.IPEnabled != "undefined" &&objObject.IPEnabled == true)
{
if(objObject.MACAddress != null &&objObject.MACAddress != "undefined")
MACAddr = objObject.MACAddress
if(objObject.IPEnabled &&objObject.IPAddress(0) != null &&objObject.IPAddress(0) != "undefined")
IPAddr = objObject.IPAddress(0)
if(objObject.DNSHostName != null &&objObject.DNSHostName != "undefined")
sDNSName = objObject.DNSHostName
}
</SCRIPT>
你想问的是ipv4和ipv6吧？ipv4地址中间是用点(.)隔开，比如192.168.0.1
ipv6地址中间使用冒号(:)隔开，比如80:0:0:0:0:0:0:1
用脚本判断就很简单了，有多种方法，
var ip
if(ip.indexOf(".")>0){
//ipv4地址
}else{
//ipv6地址
}
/^(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])$/
