阶梯电价问题 C语言#include <stdio.h>int main(){float n,costscanf("%f",&n)if(n<=110) cost=n*0.5else if(n2023-02-24Python130
C语言求阶梯电价,急急急#include <stdio.h>int main(){int mscanf("%d",&m)while(m--){float a,resultscanf("%f&quo2023-02-23Python240
r语言今年九月份用电300度需交纳电费多少200度内是每度(0.65+0.50)2=0.575元,200X0.575=115元.310-115=195元 1950.75=260度.这个月共用电200+260=460度.100X0.50=50元(200-100)X0.65=65元2023-02-20Python240