#include<stdio.h>
#include<math.h>
int main()
{
float x1,x2,,a,b,c
float deta
scanf("%f,%f,%f",&a,&b,&c)
deta=b*b-4*a*c
if(deta<0)
{
printf("方程无解")
}
else
{
x1=(-b+sqrt(deta))/(2*a)
x2=(-b-sqrt(deta))/(2*a)
printf("x1=%f,x2=%f",x1,c2)
}
return 0
}
#include <stdio.h>#include <math.h>
int main()
{
float a=5, b
b=sqrt(a)
printf("a的平方根为:%f\n",b)
return 0
}
#include<stdio.h>#include<stdlib.h>#include<math.h>int main(){ float a,b,c,x,x1,x2,d scanf("%f %f %f",&a,&b,&c) d=b*b-4*a*c if(a==0) { if(b==0) { if(0==c) { printf("等式0!\n") } else { printf("输入错误!\n") } } else { printf("只能构成一元一次方程,x=%.6f\n",0==-(float)c/b ? 0 : -(float)c/b) } } else { if(d<0) { x1=(-b+sqrt(-d))/(2.0*a) x2=(-b-sqrt(-d))/(2.0*a) printf("x1=%.6f+%.6fi\nx2=%.6f-%.6fi\n",(-b)/(2.0*a),sqrt(-d)/(2.0*a),(-b)/(2.0*a),sqrt(-d)/(2.0*a)) } else if(d==0) { printf("x1=x2=%.6f\n",(-b)/(2.0*a)) } else { x1=(-b+sqrt(d))/(2.0*a) x2=(-b-sqrt(d))/(2.0*a) printf("x1=%.6f\nx2=%.6f\n",x1,x2) } } system("PAUSE") return EXIT_SUCCESS }
