单片机C语言该怎么编写时钟程序?

Python021

单片机C语言该怎么编写时钟程序?,第1张

这个是简单的数码管时钟显示如果有需要,我写过比较完善的1602显示时钟.显示控制年月日等等.#include\x0d\x0asbit Begin=P2^0\x0d\x0asbit Hour=P2^1\x0d\x0asbit Mus=P2^2\x0d\x0asbit End=P2^3\x0d\x0aunsigned char code Tab[]={ 0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,\x0d\x0a0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x40}\x0d\x0aunsigned char code num[]={ 0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}\x0d\x0aunsigned char Time[]={0,0,16,0,0,16,0,0}\x0d\x0aunsigned char a\x0d\x0aunsigned int x,m,th\x0d\x0avoid init()\x0d\x0a{\x0d\x0a TMOD=0x01\x0d\x0a TH0=(65535/50000)/256\x0d\x0a TL0=(65535/50000)%256\x0d\x0a EA=1\x0d\x0a ET0=1\x0d\x0a TR0=1\x0d\x0a}\x0d\x0avoid delay(unsigned int z) \x0d\x0a{ \x0d\x0a unsigned int x,y\x0d\x0a for(x=zx>0x--)\x0d\x0a for(y=110y>0y--)\x0d\x0a}\x0d\x0aunsigned char keyboard()\x0d\x0a{\x0d\x0a if(Begin==0){\x0d\x0a delay(5)\x0d\x0a if(Begin==0)\x0d\x0a return 1\x0d\x0a }\x0d\x0a if(Hour==0){\x0d\x0a delay(30)\x0d\x0a if(Hour==0)\x0d\x0a return 2\x0d\x0a }\x0d\x0a if(Mus==0)\x0d\x0a return 3\x0d\x0a if(End==0)\x0d\x0a return 4\x0d\x0a}\x0d\x0avoid display()\x0d\x0a{\x0d\x0a unsigned char i for(i=0i=20)\x0d\x0a {\x0d\x0a x++\x0d\x0a m=x\x0d\x0a th=m/3600//设置小时\x0d\x0a Time[0]=th/10\x0d\x0a Time[1]=th%10\x0d\x0a m=m%3600 Time[2]=16 th=m/60//设置分钟\x0d\x0a Time[3]=th/10\x0d\x0a Time[4]=th%10\x0d\x0a m=m%60 Time[5]=16 th=m//设置秒\x0d\x0a Time[6]=th/10\x0d\x0a Time[7]=th%10 a=0\x0d\x0a }\x0d\x0a}

这个程序可以实现秒的计时,按键控制开始、暂停、清零功能,更多功能自己在看清程序的基础上进行改进。

#include <reg51.H>

sbit P3_5 =P3^5

unsigned char code dispcode[]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,

0x80,0x90,0x88,0x83,0xC6,0xA1,0x86,0x8E,0x00}

unsigned char second

unsigned char keycnt

unsigned int tcnt

void main(void)

{

unsigned char i,j

TMOD=0x02

ET0=1

EA=1

second=0

P1=dispcode[second/10]

P2=dispcode[second%10]

while(1)

{

if(P3_5==0)

{

for(i=20i>0i--)

for(j=248j>0j--)

if(P3_5==0)

{

keycnt++

switch(keycnt)

{

case 1:

TH0=0x06

TL0=0x06

TR0=1

break

case 2:

TR0=0

break

case 3:

keycnt=0

second=0

P1=dispcode[second/10]

P2=dispcode[second%10]

break

}

while(P3_5==0)

}

}

}

}

void t0(void) interrupt 1 using 0

{

tcnt++

if(tcnt==4000)

{

tcnt=0

second++

if(second==100)

{

second=0

}

P1=dispcode[second/10]

P2=dispcode[second%10]

}

}