#include <conio.h>
#include <graphics.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <ctype.h>
#include "mouse.c"
#define YES 1
#define NO 0
#define XPX 15 /* X pixels by square */
#define YPX 15 /* Y pixels by square */
#define DEFCX 30 /* Default number of squares */
#define DEFCY 28
#define MINE 255-'0' /* So that when it prints, it prints char 0xff */
#define STSQUARE struct stsquare
STSQUARE {
unsigned char value/* Number of mines in the surround squares */
unsigned char sqopen/* Square is open */
unsigned char sqpress/* Square is pressed */
unsigned char sqmark/* Square is marked */
} *psquare
#define value(x,y) (psquare+(x)*ncy+(y))->value
#define sqopen(x,y) (psquare+(x)*ncy+(y))->sqopen
#define sqpress(x,y) (psquare+(x)*ncy+(y))->sqpress
#define sqmark(x,y) (psquare+(x)*ncy+(y))->sqmark
int XST, /* Offset of first pixel X */
YST,
ncx, /* Number of squares in X */
ncy,
cmines, /* Mines discovered */
initmines, /* Number of initial mines */
sqclosed, /* Squares still closed */
maxy/* Max. number of y pixels of the screen */
void Graph_init(void)
void Read_param(int argc, char *argv[])
void Set_mines(int nminas)
void Set_square(int x, int y, int status)
void Mouse_set(void)
void Draw_squares(void)
int Do_all(void)
void Blow_up(void)
void Open_square(int x, int y)
int Open_near_squares(int x, int y)
/************************************************************************/
void main(int argc, char *argv[])
{
if (!mouse_reset()) {
cputs(" ERROR: I can't find a mouse driver\r\n")
exit(2)
}
Graph_init()
Read_param(argc, argv)
Mouse_set()
do {
randomize()
cleardevice()
Set_mines(cmines=initmines)
mouse_enable()
Draw_squares()
}
while (Do_all() != '\x1b')
closegraph()
}
/*************************************************************************
* *
* F U N C T I O N S *
* *
*************************************************************************/
/*----------------------------------------------------------------------*/
void Graph_init(void)
{
int graphdriver=DETECT, graphmode, errorcode
if(errorcode <0) {
cprintf("\n\rGraphics System Error: %s\n",grapherrormsg(errorcode))
exit(98)
}
initgraph(&graphdriver, &graphmode, "")
errorcode=graphresult()
if(errorcode!=grOk) {
printf(" Graphics System Error: %s\n",grapherrormsg(errorcode))
exit(98)
}
maxy=getmaxy()
} /* Graph_init */
/*----------------------------------------------------------------------*/
void Read_param(int argc, char *argv[])
{
int x, y, m
x=y=m=0
if (argc!=1) {
if (!isdigit(*argv[1])) {
closegraph()
cprintf("Usage is: %s [x] [y] [m]\r\n\n"
"Where x is the horizontal size\r\n"
" y is the vertical size\r\n"
" m is the number of mines\r\n\n"
" Left mouse button: Open the square\r\n"
"Right mouse button: Mark the square\r\n"
" -The first time puts a 'mine' mark\r\n"
" -The second time puts a 'possible "
"mine' mark\r\n"
" -The third time unmarks the square\r\n"
"Left+Right buttons: Open the surrounded squares only if "
"the count of mines\r\n"
" is equal to the number in the square",argv[0])
exit (1)
}
switch (argc) {
case 4: m=atoi(argv[3])
case 3: y=atoi(argv[2])
case 2: x=atoi(argv[1])
}
}
XST=100
ncx=DEFCX
if (maxy==479) {
YST=30
ncy=DEFCY
}
else {
YST=25
ncy=20
}
if (x>0 &&x<ncx)
ncx=x
if (y>0 &&y<ncy) {
YST+=((ncy-y)*YPX)>>1
ncy=y
}
initmines= m ? m : ncx*ncy*4/25/* There are about 16% of mines */
if (((void near*)psquare=calloc(ncx*ncy, sizeof(STSQUARE)))==NULL) {
closegraph()
cputs("ERROR: Not enought memory")
exit(3)
}
} /* Read_param */
/*----------------------------------------------------------------------*/
void Set_mines(int nminas)
{
"扫雷"小游戏C代码
#include<stdio.h>
#include<math.h>
#include<time.h>
#include<stdlib.h>
main( )
{char a[102][102],b[102][102],c[102][102],w
int i,j /*循环变量*/
int x,y,z[999] /*雷的位置*/
int t,s /*标记*/
int m,n,lei /*计数*/
int u,v /*输入*/
int hang,lie,ge,mo /*自定义变量*/
srand((int)time(NULL)) /*启动随机数发生器*/
leb1: /*选择模式*/
printf("\n 请选择模式：\n 1.标准 2.自定义\n")
scanf("%d",&mo)
if(mo==2) /*若选择自定义模式，要输入三个参数*/
{do
{t=0printf("请输入\n行数 列数 雷的个数\n")
scanf("%d%d%d",&hang,&lie,&ge)
if(hang<2){printf("行数太少\n")t=1}
if(hang>100){printf("行数太多\n")t=1}
if(lie<2){printf("列数太少\n")t=1}
if(lie>100){printf("列数太多\n")t=1}
if(ge<1){printf("至少要有一个雷\n")t=1}
if(ge>=(hang*lie)){printf("雷太多了\n")t=1}
}while(t==1)
}
else{hang=10,lie=10,ge=10} /*否则就是选择了标准模式(默认参数)*/
for(i=1i<=gei=i+1) /*确定雷的位置*/
{do
{t=0z[i]=rand( )%(hang*lie)
for(j=1j<ij=j+1){if(z[i]==z[j]) t=1}
}while(t==1)
}
for(i=0i<=hang+1i=i+1) /*初始化a,b,c*/
{for(j=0j<=lie+1j=j+1) {a[i][j]='1'b[i][j]='1'c[i][j]='0'} }
for(i=1i<=hangi=i+1)
{for(j=1j<=liej=j+1) {a[i][j]='+'} }
for(i=1i<=gei=i+1) /*把雷放入c*/
{x=z[i]/lie+1y=z[i]%lie+1c[x][y]='#'}
for(i=1i<=hangi=i+1) /*计算b中数字*/
{for(j=1j<=liej=j+1)
{m=48
if(c[i-1][j-1]=='#')m=m+1if(c[i][j-1]=='#')m=m+1
if(c[i-1][j]=='#')m=m+1 if(c[i+1][j+1]=='#')m=m+1
if(c[i][j+1]=='#')m=m+1 if(c[i+1][j]=='#')m=m+1
if(c[i+1][j-1]=='#')m=m+1if(c[i-1][j+1]=='#')m=m+1
b[i][j]=m
}
}
for(i=1i<=gei=i+1) /*把雷放入b中*/
{x=z[i]/lie+1y=z[i]%lie+1b[x][y]='#'}
lei=ge /*以下是游戏设计*/
do
{leb2: /*输出*/
system("cls")printf("\n\n\n\n")
printf(" ")
for(i=1i<=liei=i+1)
{w=(i-1)/10+48printf("%c",w)
w=(i-1)%10+48printf("%c ",w)
}
printf("\n |")
for(i=1i<=liei=i+1){printf("---|")}
printf("\n")
for(i=1i<=hangi=i+1)
{w=(i-1)/10+48printf("%c",w)
w=(i-1)%10+48printf("%c |",w)
for(j=1j<=liej=j+1)
{if(a[i][j]=='0')printf(" |")
else printf(" %c |",a[i][j])
}
if(i==2)printf(" 剩余雷个数")
if(i==3)printf(" %d",lei)
printf("\n |")
for(j=1j<=liej=j+1){printf("---|")}
printf("\n")
}
scanf("%d%c%d",&u,&w,&v) /*输入*/
u=u+1,v=v+1
if(w!='#'&&a[u][v]=='@')
goto leb2
if(w=='#')
{if(a[u][v]=='+'){a[u][v]='@'lei=lei-1}
else if(a[u][v]=='@'){a[u][v]='?'lei=lei+1}
else if(a[u][v]=='?'){a[u][v]='+'}
goto leb2
}
a[u][v]=b[u][v]
leb3: /*打开0区*/
t=0
if(a[u][v]=='0')
{for(i=1i<=hangi=i+1)
{for(j=1j<=liej=j+1)
{s=0
if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1
if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1
if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1
if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1
if(s==1)a[i][j]=b[i][j]
}
}
for(i=1i<=hangi=i+1)
{for(j=liej>=1j=j-1)
{s=0
if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1
if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1
if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1
if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1
if(s==1)a[i][j]=b[i][j]
}
}
for(i=hangi>=1i=i-1)
{for(j=1j<=liej=j+1)
{s=0
if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1
if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1
if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1
if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1
if(s==1)a[i][j]=b[i][j]
}
}
for(i=hangi>=1i=i-1)
{for(j=liej>=1j=j-1)
{s=0
if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1
if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1
if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1
if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1
if(s==1)a[i][j]=b[i][j]
}
}
for(i=1i<=hangi=i+1) /*检测0区*/
{for(j=1j<=liej=j+1)
{if(a[i][j]=='0')
{if(a[i-1][j-1]=='+'||a[i-1][j-1]=='@'||a[i-1][j-1]=='?')t=1
if(a[i-1][j+1]=='+'||a[i-1][j+1]=='@'||a[i-1][j+1]=='?')t=1
if(a[i+1][j-1]=='+'||a[i+1][j-1]=='@'||a[i+1][j-1]=='?')t=1
if(a[i+1][j+1]=='+'||a[i+1][j+1]=='@'||a[i+1][j+1]=='?')t=1
if(a[i+1][j]=='+'||a[i+1][j]=='@'||a[i+1][j]=='?')t=1
if(a[i][j+1]=='+'||a[i][j+1]=='@'||a[i][j+1]=='?')t=1
if(a[i][j-1]=='+'||a[i][j-1]=='@'||a[i][j-1]=='?')t=1
if(a[i-1][j]=='+'||a[i-1][j]=='@'||a[i-1][j]=='?')t=1
}
}
}
if(t==1)goto leb3
}
n=0 /*检查结束*/
for(i=1i<=hangi=i+1)
{for(j=1j<=liej=j+1)
{if(a[i][j]!='+'&&a[i][j]!='@'&&a[i][j]!='?')n=n+1}
}
}
while(a[u][v]!='#'&&n!=(hang*lie-ge))
for(i=1i<=gei=i+1) /*游戏结束*/
{x=z[i]/lie+1y=z[i]%lie+1a[x][y]='#'}
printf(" ")
for(i=1i<=liei=i+1)
{w=(i-1)/10+48printf("%c",w)
w=(i-1)%10+48printf("%c ",w)
}
printf("\n |")
for(i=1i<=liei=i+1){printf("---|")}
printf("\n")
for(i=1i<=hangi=i+1)
{w=(i-1)/10+48printf("%c",w)
w=(i-1)%10+48printf("%c |",w)
for(j=1j<=liej=j+1)
{if(a[i][j]=='0')printf(" |")
else printf(" %c |",a[i][j])
}
if(i==2)printf(" 剩余雷个数")
if(i==3)printf(" %d",lei)printf("\n |")
for(j=1j<=liej=j+1) {printf("---|")}
printf("\n")
}
if(n==(hang*lie-ge)) printf("你成功了!\n")
else printf(" 游戏结束!\n")
printf(" 重玩请输入1\n")
t=0
scanf("%d",&t)
if(t==1)goto leb1
}
/*注：在DEV c++上运行通过。行号和列号都从0开始，比如要确定第0行第9列不是“雷”，就在0和9中间加入一个字母，可以输入【0a9】三个字符再按回车键。3行7列不是雷，则输入【3a7】回车；第8行第5列是雷，就输入【8#5】回车，9行0列是雷则输入【9#0】并回车*/
#include<stdio.h>int main(void)
{
char plat[100][100] //雷的地图
char plat_new[100][100] //数字映射图
int n, m //存储行、列数
int in, im
int mark = 0 //记录该点附近8个坐标雷的总数
int j = 1
scanf("%d %d", &n, &m)
getchar() //消除回车符的影响
do {
if (n == 0 && m == 0)
break
for (in = 0 in < n in++)
{
for (im = 0 im < m im++)
{
scanf("%c", &plat[in][im])
}
getchar()
}
for (in = 0 in < n in++)
for (im = 0 im < m im++)
{
if (plat[in][im] == '*') /*该点有雷，无需检测*/
{
plat_new[in][im]= plat[in][im]
continue
}
if (in - 1 >= 0) //检测上面3个点的雷数
{
if (plat[in - 1][im] == '*')
mark++
if (im - 1 >= 0 && plat[in -1][im - 1] == '*')
mark++
if (im + 1 < m&&plat[in -1][im + 1] == '*')
mark++
}
if (im - 1 >= 0 && plat[in][im- 1] == '*') //检测左右两个点的雷数
mark++
if (im + 1 < m && plat[in][im+ 1] == '*')
mark++
if (in + 1 < n) //检测下面3个点的雷数
{
if (plat[in + 1][im] == '*')
mark++
if (im - 1 >= 0 && plat[in +1][im - 1] == '*')
mark++
if (im + 1 < m&&plat[in +1][im + 1] == '*')
mark++
}
switch (mark)
{
case 0:plat_new[in][im] = '0' break
case 1:plat_new[in][im] = '1' break
case 2:plat_new[in][im] = '2' break
case 3:plat_new[in][im] = '3' break
case 4:plat_new[in][im] = '4' break
case 5:plat_new[in][im] = '5' break
case 6:plat_new[in][im] = '6' break
case 7:plat_new[in][im] = '7' break
case 8:plat_new[in][im] = '8' break
}
mark = 0 //重置雷数
}
if (j != 1)
putchar('\n')
printf("Field#%d:\n", j)
for (in = 0 in < n in++) //打印数字地图
{
for (im = 0 im < m im++)
{
printf("%c", plat_new[in][im])
}
if(in!=n-1)
putchar('\n')
}
scanf("%d %d", &n, &m)
getchar()
j++
} while (1)
return 0
}
