分层随机化中，我们在进行分层后最终根据患者的不同特征把患者分为了各个亚组，再此分为了4个亚组，然后根据治疗方案（纳入治疗组还是对着组）对患者进行简单随机化。
但是，当总体样本量或每个亚组的样本量的不大时，在每个亚组进行简单随机化容易产生两组间治疗组及试验租的患者发生不平衡的情况（比如10个人随机分组，很容易出现一组7人一组3人的情况）。这时，我们可以引入区组随机化。比如，研究对象共计80例患者，所有层及水平均等分入组，每个亚组20例患者。如果对20例患者进行简单随机化很容易产生一组患者人多，一组患者人少的情况。这时候我们利用区组随机化，比如可以设定组的大小为4，强制前4个患者2个治疗组2个对照组，这样可以解决此类问题。
但是如果固定组的大小，每个组别的最后患者就会知道期分组情况，比如下图，固定区组大小为4，最后的患者再未进行分组前就能知道期为B治疗方案，不利于隐蔽分组的实现。
R语言中的blockrand包在对患者进行分层后，可以对每个层内的每个水平患者进行区组大小不固定的随机化，如下图
医科看到，前这四个患者的组大小为4，后续为2。而此分组大小是软件根据每个亚组的人数随机产生的。这样，就无法提前判断患者的入组情况。
详细说明网站
https://rdrr.io/cran/blockrand/man/blockrand.html
我的亲师弟最近也开始学习R语言了，然后师弟每天“师姐，师姐..."，“我这个怎么弄...”，“我怎么又报错了...”，“师姐师姐...”...我快被他搞疯了，于是有了这篇文章。
新手在学习R语言的过程中一定会出现各种各种问题，问题多到令人抓耳挠腮。
但其实不要觉得害怕或有打退堂鼓的心里，R的使用，就是不断报错不断找问题的过程。但是出现问题，第一反应一定要是上网搜索，找答案，不要第一时间就问身边的人，错失了思考的过程。生信的学习，其实就是一个漫长的自学过程。
推荐 搜索引擎：必应，必应，必应 ！不要再用某度啦拜托！当然如果你能想办法用Google，那当然再好不过了。
搜索能解决百分之九十以上的问题 ，就算解决不了，如果解决不了，可能是因为你的搜索能力还不够高。在这个搜索、尝试解决以及思考的过程，对新学者来说也是一大收获。本身搜索能力的提升就是一个巨大收获。
如果自己尝试了好久，最终实在解决不了，那。。。就再去请教有经验的前辈吧~
其实这种搜索并独立解决问题的思维，我还是在同济大学， 生信大牛刘小乐教授 课题组学到的。刘小乐教授课题组每年都有为期一个月的生信培训，本人有幸学习过一段时间。她们会给很多生信相关的题目给到学员，然后附上一些教学视频，培训的大部分时间，其实就是写作业，自己想方设法找到解决方案的过程。那些大牛师兄师姐们虽然一直在陪伴我们，但是并不会直接告诉我们答案，而是引导我们自己思考，自己去解决。当时真的很崩溃，因为真的啥也不会，怎么搞。一天下来有可能一个问题都答不上来。
但是现在回头想想，我真的获益良多。因为我慢慢学会了独立思考，现在遇到R相关的问题，配合上搜索功能，基本上已经完全能自己驾驭了。
这可能就是“ 授人以鱼不如授人以渔 ”的道理吧。
R语言很简单，只要你想学，就一定能学会。
以下附上同济大学刘小乐课题组在培训时针对初学者第一周的初级练习题。希望对大家有所帮助。
首先你需要先安装几个最常用的数据处理软件
You can use the mean() function to compute the mean of a vector like
so:
However, this does not work if the vector contains NAs:
Please use R documentation to find the mean after excluding NA's (hint: ?mean )
In this question, we will practice data manipulation using a dataset
collected by Francis Galton in 1886 on the heights of parents and their
children. This is a very famous dataset, and Galton used it to come up
with regression and correlation.
The data is available as GaltonFamilies in the HistData package.
Here, we load the data and show the first few rows. To find out more
information about the dataset, use ?GaltonFamilies .
a. Please report the height of the 10th child in the dataset.
b. What is the breakdown of male and female children in the dataset?
c. How many observations are in Galton's dataset? Please answer this
question without consulting the R help.
d. What is the mean height for the 1st child in each family?
e. Create a table showing the mean height for male and female children.
f. What was the average number of children each family had?
g. Convert the children's heights from inches to centimeters and store
it in a column called childHeight_cm in the GaltonFamilies dataset.
Show the first few rows of this dataset.
In the code above, we generate r ngroups groups of r N observations
each. In each group, we have X and Y, where X and Y are independent
normally distributed data and have 0 correlation.
a. Find the correlation between X and Y for each group, and display
the highest correlations.
Hint: since the data is quite large and your code might take a few
moments to run, you can test your code on a subset of the data first
(e.g. you can take the first 100 groups like so):
In general, this is good practice whenever you have a large dataset:
If you are writing new code and it takes a while to run on the whole
dataset, get it to work on a subset first. By running on a subset, you
can iterate faster.
However, please do run your final code on the whole dataset.
b. The highest correlation is around 0.8. Can you explain why we see
such a high correlation when X and Y are supposed to be independent and
thus uncorrelated?
Show a plot of the data for the group that had the highest correlation
you found in Problem 4.
We generate some sample data below. The data is numeric, and has 3
columns: X, Y, Z.
a. Compute the overall correlation between X and Y.
b. Make a plot showing the relationship between X and Y. Comment on
the correlation that you see.
c. Compute the correlations between X and Y for each level of Z.
d. Make a plot showing the relationship between X and Y, but this
time, color the points using the value of Z. Comment on the result,
especially any differences between this plot and the previous plot.
