python eval()方法将字符串转换为元组

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python eval()方法将字符串转换为元组,第1张

python eval()方法字符串转换为元组

从文件中读取如下数据:

简单粗暴的方法:eval(line)就能将读取的行数据变成tuple类型,通过下标就可以获取数据了。

li = [1, 2, 3]

t = tuple(li)

print(t, type(t))

del list #先清除list缓存

tu = (1, 2, 3)

li = list(tu)

print(li, type(li))

li = ['人', '生', '苦', '短']

str1 = ''.join(li)

print(str1, type(str1))

str2 = 'hello python'

li1 = str2.split(' ')

print(li1, type(li1))

list1 = ['name', 'age', 'sex']

list2 = ['张三', 18, '男']

dict = {}

for i in range(len(list1)):

dict[list1[i]] = list2[i]

print(dict, type(dict))

del dict#清除缓存

list1 = ['name', 'age', 'sex']

list2 = ['张三', 18, '男']

d = dict(zip(list1, list2))

print(d)

dict = {'name': '张三', 'age': 18, 'sex': '男'}

keys = list(dict.keys())

values = list(dict.values())

print(keys, type(keys))

print(values, type(values))

list3 = [['key1','value1'],['key2','value2'],['key3','value3']]

print(dict(list3))

list1 = [1, 3, 4, 3, 2, 1]

s1 = set(list1)

print(s1, type(s1))

list1 = [1, 3, 4, 3, 2, 1]

s1 = set(list1)

list2 = list(s1.intersection(s1))

print(list2, type(list2))

list = []

a = '人生苦短'

list.append(a)

print(list)

b = tuple(list)

print(b, type(b))

dict = {'name': 'xiaoming', 'age': 18}

tup = tuple(dict)

print(tup) # 只转换了key

tup2 = tuple(dict.values())

print(tup2)

dic1 = {'a': 1, 'b': 2}

str1 = str(dic1)

dic2 = eval("{'name':'xiaoming', 'age':18}")

print(dic2, type(dic2))

str1 = 'hello'

s1 = set(str1)

print(s1, type(s1))

dic1 = {'a': 1, 'b': 2, 'c': 3}

dic2 = {value: key for key, value in dic1.items()}

print(dic2)

list_in = ['1\t2\n', '4\t7\n']

list_out = [tuple(i.strip().split()) for i in list_in]