ruby怎么实现数组减法

Python022

ruby怎么实现数组减法,第1张

数组的创建和初始化

a = Array.[](1,2,3,4)

b = Array[1,2,3,4]

c = [1,2,3,4]

d = Array.new #创建一个空数组

e = Array.new(3) #[nil,nil,nil] 初始大小3

f = Array.new(3,"xx") #["xx","xx","xx"] 初始大小3 初始值"xx"

f[0].capitalize! #=>["Xx","Xx","Xx"]

g = Array.new(3){"yy"} #=>["yy","yy","yy"]

g[0].capitalize! #=>["Yy","yy","yy"]

public static void main(String[] args)

{

int [] num =new int[]{1,2,3,4,5,6,7,8,9,10}

Scanner input = new Scanner(System.in)

int temp=0

System.out.println("请输入你要删除的元素:")

int de=input.nextInt()

for(int i =0i<num.lengthi++)

{

if(num[i]==de)

{

for(int j = ij<num.length-1j++)

{

num[j]=num[j+1]

}

temp=1

break

}

}

if(temp==1)

{

System.out.println("删除此对象后数组值为：")

for(int i = 0i<num.length-1i++)

{

System.out.print(num[i]+"\t")

}

}

else

{

System.out.println("未找到你要删除的对象")

}

}