int change(int amount, int index, int const coins[]) {
if(amount == 0) return 1
if(index <= 0) return 0
for(int i = amount / coins[index - 1] i >= 0 --i) {
if(change(amount - i * coins[index - 1], index - 1, coins)) {
if(i)
printf(" %d*%d", i, coins[index - 1])
return 1
}
}
return 0
}
int main()
{
int coins[] = { 20, 50}
int const size = sizeof(coins)/ sizeof(int)
int amount
for(int i = 0 i < size ++i) {
for(int j = i + 1 j < size ++j) {
if(coins[i] > coins[j]) {
int temporary = coins[i]
coins[i] = coins[j]
coins[j] = temporary
}
}
}
if(coins[0] <= 0) {
printf("数据有误,零钱必须大于0\n")
return -1
}
printf("请输入要兑换的货币金额: ")
scanf("%d", &amount)
if(change(amount, size, coins))
printf("\n兑换成功\n")
else printf("\n兑换失败\n")
return 0
}
#includeint main() {
int i,x,n,*result = NULL
int a[10],low,high,mid
scanf_s("%d",&n)
// 确保输入的数据是非递减的
for(i = 0 i <n &&i <10 i++) {
scanf_s("%d",&a[i])
}
fflush(stdin)// 如果输入的数组元素多于10个,则废弃
scanf_s("%d",&x)
low = 0,high = n - 1
while(low <= high) {
mid = (low + high) / 2
if(x == a[mid]) {
result = &a[mid]// 这里给出的是查找到该元素的指针
break
}
else if(x <a[mid]) {
high = mid - 1
}
else {
low = mid + 1
}
}
if(result != NULL) {
printf("%d\n",*result)
}
else {
printf("no result\n")
}
return 0
}