import java.util.Scanner
public class Cat {
public static void main(String[] args) {
System.out.print("Please input 2 numbers:")
String[] input = new Scanner(System.in).nextLine().trim().split("\\s+")
BigDecimal num1 = new BigDecimal(input[0])
int num2 = Integer.parseInt(input[1])
BigDecimal mul = new BigDecimal("1.0")
for(int i = 1i <= num2i++){
mul = mul.multiply(num1)
}
System.out.println(mul.toString())
}
}
------------------testing
Please input 2 numbers:95.123 12
548815620517731830194541.8990253434157159735359672218698527210
import java.util.Scannerpublic class test005 {
double myPow(double x, int y) {
double pow = 0
if (y >0) {
pow = x * myPow(x, y - 1)// 2,3//2*2,3-1
}
if (y <0) {
pow = 1 / x * myPow(x, y + 1)
}
if (y == 0) {
pow = 1
}
return pow
}
void count() {
System.out.println("please input base number and index number")
double base = new Scanner(System.in).nextInt()
int index = new Scanner(System.in).nextInt()
double result = myPow(base, index)
System.out.println(result)
}
public static void main(String[] s) {
new test005().count()
}
}
方法一：public class TestMath{
public static void main(String[] args){
System.out.println("2^3="+Math.pow(2,3)) //直接调用Java中求幂的方法pow(),输出的结果为2的3次幂。
}
}
方法二：
public calss Test{
public static void main(String[] args){
//示例：求3的5次幂
int a=3
int b=5
for(int i=1i<bi++)
a*=a
System.out.println("3的5次幂等于"+a)
}
}
