其中,年份系数我以2007年做参照,已知2007年,年份系数是0,往前往后分别是递减和递增。增减规律:非闰年为±1,闰年1~2月-2或+1,闰年3~12月+2或者-1。
其中,12个月份系数对应:0,3,3,6,1,4,6,2,5,0,3,5。
根据以上规律,只要利用循环,就可以的到对应系数和星期。
日历实现翻页功能,按键盘左右方向键可以翻译查看当年其他月份,按向上方向键可以返回菜单。
下面是代码:
#include <stdio.h>
#include <malloc.h>
#include <string.h>
#include <conio.h>
#include <math.h>
#include <time.h>
#define XY 2007
#define X07 0//以2007年年系数0做参照
int isLeapYear(int year)//判断是否是闰年,是返回1,否返回0
int addyx(int yx,int n)//年系数自增,0~6,n:自增的跨度,返回自增后的年系数
int getYX(int year,int month)//获得年系数0~6
int getMX(int month)//获得月系数
int getWeek(int yx,int mx,int day)//通过年月系数(yx:年系数;mx:月系数)及日期获取星期
char *getStrWeek(int yx,int mx,int day)//通过年月系数(yx:年系数;mx:月系数)及日期获取星期对应的中文字符串
int getMaxDay(int year,int month)//通过年月获取当月最大天数
void prCalendar(int year,int month)//打印日历
int showMeun()//打印主菜单
int getDuration(int year,int month,int day)//通过日期获取距今天数
int calendar[6][7]
int main()
{
//int year,month,day,yx,mx
while(1)
{
if(!showMeun())
break
}
return 0
}
int showMeun()//打印主菜单
{
int n,year,month,day,yx,mx
while(1)
{
system("cls")
printf("1、输入年份,显示该年每个月的日历\n")
printf("2、输入年月,显示该月的天数\n")
printf("3、输入日期,显示距离今天的天数\n")
printf("4、输入日期,查询这一天是星期几\n")
printf("0、结束程序\n")
n=-1,year=0,month=0,day=0
while(n<0 || n>4)
{
printf("请输入选择的菜单序号:")
scanf("%d",&n)
}
switch(n)
{
case 1:while(year<=0 || year>9999)
printf("请输入年份:"),scanf("%d",&year)
prCalendar(year,1)
break
case 2:while(year<=0 || year>9999 || month<=0 || month>12)
printf("请输入年份及月份:"),scanf("%d%d",&year,&month)
printf("%4d年%2d月共有%d天\n按任意键继续。。。。。。\n",year,month,getMaxDay(year,month)),getch()
break
case 3:while(year<=0 || year>9999 || month<=0 || month>12 || day<0 || day>getMaxDay(year,month))
printf("请输入日期:"),scanf("%d%d%d",&year,&month,&day)
printf("距离今日有%d天\n按任意键继续。。。。。。\n",getDuration(year,month,day)),getch()
break
case 4:while(year<=0 || year>9999 || month<=0 || month>12 || day<0 || day>getMaxDay(year,month))
printf("请输入日期:"),scanf("%d%d%d",&year,&month,&day)
yx=getYX(year,month)
mx=getMX(month)
printf("%4d年%2d月%2d日是%s\n按任意键继续。。。。。。\n",year,month,day,getStrWeek(yx,mx,day)),getch()
break
case 0:return 0
}
}
return n
}
void prCalendar(int year,int month)//打印日历
{
char c1,c2
int i,j,*p=NULL,yx,mx,cnt,w,maxDay
while(1)
{
p=&calendar[0][0]
yx=getYX(year,month),mx=getMX(month)
cnt=0,w=getWeek(yx,mx,1)
maxDay=getMaxDay(year,month)
for(i=0i<6i++)
for(j=0j<7j++)
{
if(cnt<w)
p++,cnt++
calendar[i][j]=0
}
for(i=1i<=maxDayi++)
*p=i,p++
system("cls")
printf(" %4d 年%2d月 \n",year,month)
printf("日 一 二 三 四 五 六\n")
for(i=0i<6i++,printf("\n"))
for(j=0j<7j++)
if(calendar[i][j]==0)
printf(" ")
else
printf("%2d ",calendar[i][j])
printf("<- 按方向键向左或向右翻页 ->\n")
printf(" 按向上方向键返回主菜单\n")
c1=getch()
c2=getch()
if(c1==-32 &&c2==75)//左键
{
if(month==1)
month=12
else
month--
}
if(c1==-32 &&c2==77)//右键
{
if(month==12)
month=1
else
month++
}
if(c1==-32 &&c2==72)//上键
{
showMeun()
break
}
}
}
int getDuration(int year,int month,int day)//通过日期获取距今天数
{
int i,y,m,d,sum=0,sum2=0,minY,maxY,minM,maxM,minD,maxD
time_t tt
struct tm *tmp
time(&tt)
tmp=localtime(&tt)
y=1900+tmp->tm_year,m=1+tmp->tm_mon,d=tmp->tm_mday//获取当前日期的年月日
if(year<y)
minY=year,maxY=y,minM=month,maxM=m,minD=day,maxD=d
if(year>y)
minY=y,maxY=year,minM=m,maxM=month,minD=d,maxD=day
if(year!=y)
{
for(i=minYi<maxYi++)//按相差年份累加(不包含右端最大年份)
if(isLeapYear(i))
sum+=366//闰年
else
sum+=365
for(i=1i<minMi++)//扣除左端年份已过月份对应天数
sum-=getMaxDay(minY,i)
sum-=minD//扣除左端当月已过天数
for(i=1i<maxMi++)//累加右端最大年份已过月份对应天数(不包含最大年份当月)
sum+=getMaxDay(maxY,i)
sum+=maxD//累加右端当月已过天数
}
else//如果年份相同,累加两边一年内已过天数,求差值
{
for(i=1i<monthi++)
sum+=getMaxDay(month,i)
sum+=day
for(i=1i<mi++)
sum2+=getMaxDay(m,i)
sum2+=d
return abs(sum2-sum)
}
return sum
}
int getMaxDay(int year,int month)//通过年月获取当月最大天数
{
int days[12]={31,28,31,30,31,30,31,31,30,31,30,31}
if(isLeapYear(year) &&month==2)
return days[month-1]+1
return days[month-1]
}
char *getStrWeek(int yx,int mx,int day)//通过年月系数(yx:年系数;mx:月系数)及日期获取星期对应的中文字符串
{
int w
static char week[7]
memset(week,0,7)
strcpy(week,"星期")
w=getWeek(yx,mx,day)
switch(w)
{
case 0:strcat(week,"日")break
case 1:strcat(week,"一")break
case 2:strcat(week,"二")break
case 3:strcat(week,"三")break
case 4:strcat(week,"四")break
case 5:strcat(week,"五")break
case 6:strcat(week,"六")break
}
return week
}
int getWeek(int yx,int mx,int day)//通过年月系数(yx:年系数;mx:月系数)及日期获取星期对应的数值0~6
{
return (yx+mx+day)%7
}
int getMX(int month)//获得月系数
{
int xmonth[12]={0,3,3,6,1,4,6,2,5,0,3,5}//月系数:1-12月,每月的系数。
return xmonth[month-1]
}
int getYX(int year,int month)//获得年系数0~6
{
int yx=0,nyear=XY,isly,flag
if(nyear==year)
return 0
if(nyear<year)
flag=0,nyear++
else
flag=1,nyear--
while(1)
{
isly=isLeapYear(nyear)
if(!isly){//非闰年年系数累加1
if(!flag)
yx=addyx(yx,1)
else
yx=addyx(yx,-1)
}
if(isly &&month>=1 &&month<=2){//闰年1~2月年系数累加1,3`12月年系数累加2
if(!flag)
yx=addyx(yx,1)
else
yx=addyx(yx,-2)
}
else if(isly &&month>=3 &&month<=12){
if(!flag)
yx=addyx(yx,2)
else
yx=addyx(yx,-1)
}
if(nyear==year)
break
if(!flag &&nyear<year)
nyear++
if(flag &&nyear>year)
nyear--
}
return yx
}
int addyx(int yx,int n)//年系数自增,0~6,n:自增的跨度,返回自增后的年系数
{
if(n>0)
{
if(yx+n<=6)
return yx+n
if(yx+n>6)
return yx+n-7
}
if(n<0)
{
if(yx+n>=0)
return yx+n
if(yx+n<0)
return yx+n+7
}
return -1
}
int isLeapYear(int year)//判断是否是闰年,是返回1,否返回0
{
if((year%4==0 &&year%100!=0)||(year%400==0))
return 1
return 0
}
1、首先要判断一个年份是闰年还是平年,用一个子程序来做。
2、然后就开始写主程序,首先用scanf得到一个年份。
3、在判断这个年份是平年还是闰年后用printf在CMD中打印出来。
4、在编写完成后,在Notepad++界面下按下F5,弹出输入框。
5、cmd /k gcc -o "$(CURRENT_DIRECTORY)\$(NAME_PART).exe""$(FULL_CURRENT_PATH)" &&CLS &&"$(CURRENT_DIRECTORY)\$(NAME_PART).exe" &PAUSE &EXIT。在输入框例输入后运行。
6、点击运行,会弹出CMD,在里面输入年份后回车就完成了。
/*C语言编程万年历要求输入年月,判断是否闰年;
输入年月日,判断星期几;
输入年份,打出12个月的月历;
输入年份,月份,打印出本月日历;
要求用多个函数实现。*/
#include<stdio.h>
#include<time.h>
#include<string.h>int calendar[12][6][7]/*月历*/
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Satarday"}
char* Monthname[]={"January","February","March","April","May","June","July",
"August","September","October","November","December"}
int monthday[]={31,28,31,30,31,30,31,31,30,31,30,31}
char* menu[]={/*操作菜单*/
"1.Input a year number,check whether it's a leap year.\n",
"2.Input year,month,day,check the weekday.\n",
"3.Input year,month,output the calendar of that month.\n",
"4.Input year,output all the month calendar.\n",
"0.Exit.\n"
}/*判断参数year传递的年份是否是闰年*/
int IsLeapyear(int year)
{
if(!(year%4)&&year%100||!(year%400)) return 1
else return 0
}/*输入年月日,判断星期几,利用Zeller公式w=y+[y/4]+[c/4]-2c+[26(m+1)/10]+d-1
w是结果星期数,y是年份的后两位,c是年份的前两位,m是月份,3≤m≤14,也就是当
m≤2时,要算到前一年的13月份和14月份,最后要将w对7取模
*/
int WeekDay(int year,int month,int day)
{
int w,y,c,m,d
c=year/100
if(month<3){
m=12+month
y=year%100-1
}
else{
m=month
y=year%100
}
d=day
w=y+y/4+c/4-2*c+26*(m+1)/10+d-1
return (w%7+7)%7
}/*输入年份,月份,打印出本月的日历*/
void Monthly(int year,int month)
{
int weekday,i,j
if(month==2)
if(IsLeapyear(year)) monthday[1]+=1
weekday=WeekDay(year,month,1)
printf("%s\n",Monthname[month-1])
printf("Sun. Mon. Tue. Wed. Thu. Fri. Sat.\n")
for(i=1,j=weekdayi<=monthday[month-1]i++,j++){
calendar[month-1][j/7][j%7]=i
}
for(i=0i<6i++){
for(j=0j<7j++)
{
if(calendar[month-1][i][j]==0) printf("%5c",' ')
else printf("%-5d",calendar[month-1][i][j])
}
printf("\n")
}
}void allMonth(int year) /*输入年份,打印出12个月的月历*/
{
int i
for(i=1i<=12i++){
Monthly(year,i)
getch()/*按任意键继续执行*/
}
}void main(void)
{
int year,month,day,i,n,weekday
memset(&calendar,sizeof(calendar),0) /*初始化月历*/
for(i=0i<5i++)
printf("%s",menu[i])
while(1){
printf("Please choose the menu:")
scanf("%d",&n)
printf("\n")
switch(n){
case 1:
printf("Please input year:")
scanf("%d",&year)
if(IsLeapyear(year)) printf("\n%d is leap year.\n",year)
else printf("%d isn't leap year.\n",year)
break
case 2:
printf("Please input year month day:")
scanf("%d%d%d",&year,&month,&day)
printf("\n")
weekday=WeekDay(year,month,day)
printf("That day is %s\n",week[weekday])
break
case 3:
printf("Please input year month,then it output a calendar of that month:")
scanf("%d%d",&year,&month)
printf("\n")
Monthly(year,month)
break
case 4:
printf("Please input year,then it will output the calendar of that year:")
scanf("%d",&year)
printf("\n")
allMonth(year)
break
case 0:
return
default:
printf("The number you input is invalid.\n")
break
}
}
getch() /*按任意键,程序退出*/
}这个程序是可用的~~希望能帮到你~~~